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Dec 7, 2022 at 18:20 comment added Xi'an The density of the ordered sample is $n!$ times the density of the unordered one.
Dec 7, 2022 at 17:13 comment added mjc @Xi'an I'm afraid I don't understand. How does the ordering of the data affect the equality of the joint pdf to the product of the individual pdfs?
Dec 7, 2022 at 17:10 comment added mjc @AdamO Thanks, that's a relief to have confirmed. The proportionality you mention is actually added as a further step in the notes, which I omitted from my quote, but the notes do as quoted use the $\propto$ sign for the first step, between $f$ and the product with the proportionality constant.
Dec 7, 2022 at 17:06 comment added AdamO I would agree calling $f$ a likelihood is an abuse of terminology. It's also bizarre, most obviously it's a density function, but then the "propto" symbol is there, but they have included the normalizing constant. Much easier to write $f(x|\theta) \propto \exp(c (x_i - \theta) ^2) $
Dec 7, 2022 at 17:02 comment added Xi'an Still, the density of the data could be proportional to the rhs if, e.g., the data is produced in an ordered way, with $x_1<x_2<\cdots$.
Dec 7, 2022 at 16:43 history edited mjc CC BY-SA 4.0
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Dec 7, 2022 at 16:35 history asked mjc CC BY-SA 4.0