I think a simple chi-squared test will do the trick. Do you have 1,000,000 observations for both control and test? If so, your table of observations will be (in R code)
Edit: Woops! Left ofoff a zero!
m <- rbind(c(3, 1000000-3), c(10, 1000000-10))
# [,1] [,2]
# [1,] 3 999997
# [2,] 10 999990
And chi-squared test will be
chisq.test(m)
Which returns chi-squared = 2.7692, df = 1, p-value = 0.0961, which is not statistically significant at the p < 0.05 level. I'd be surprised if these could be clinically significant anyway.