How can we use this as a basis to decide the best regression fit model? Not many question posts included the concept of Adjusted R-squared for understanding.
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$\begingroup$ Possible duplicate of What's the difference between multiple R and R squared? $\endgroup$– JohnCommented Oct 20, 2016 at 5:09
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4$\begingroup$ @John the previous question didn't relate to adjusted R squared. $\endgroup$– Gordon SmythCommented Oct 20, 2016 at 5:32
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$\begingroup$ Yeah its not a duplicate, I didnt find the explanation for adjusted R squared $\endgroup$– Rohit Venkat Gandhi MendadhalaCommented Oct 20, 2016 at 6:32
1 Answer
I wont go into the real maths of it (as I don't understand it myself), but I can explain it in more general terms.
Multiple R squared is simply a measure of Rsquared for models that have multiple predictor variables. Therefore it measures the amount of variation in the response variable that can be explained by the predictor variables. The fundamental point is that when you add predictors to your model, the multiple Rsquared will always increase, as a predictor will always explain some portion of the variance.
Adjusted Rsquared controls against this increase, and adds penalties for the number of predictors in the model. Therefore it shows a balance between the most parsimonious model, and the best fitting model. Generally, if you have a large difference between your multiple and your adjusted Rsquared that indicates you may have overfit your model.
Hope this helps. Hopefully someone may come along and explain this more in depth.
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2$\begingroup$ The Wikipedia article on Coefficients of determination covers $r^2$, $R^2$ as well as the adjusted R squared: $\bar{R}^2$ en.wikipedia.org/wiki/Coefficient_of_determination#Adjusted_R2 $\endgroup$– BeyerCommented Oct 20, 2016 at 7:20
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$\begingroup$ Why should both be different when you have only one variable (beyond the intercept)? Does it mean both will never be the same? $\endgroup$– RodrigoCommented Jan 17, 2021 at 20:57