For an $r \times c$ contingency table, the cells containing observed frequencies, the null hypothesis "the row and column variables are independent" is typically tested by using a $\chi^2$ chisquare test. The quantity
$$X^2 = \sum{\dfrac{(O-E)^2}{E}}$$
is used, with $O$ denoting the observed frequency in a cell and $E$ the expected frequency in a cell under independence; the summation is over all cells in the table. Under the null hypothesis of independence (and the additional condition that all expected frequencies are "large enough") $X^2$ follows a $\chi^2$ distribution with $(r-1) \times (c-1)$ degrees of freedom, which we can use to statistically test the null hypothesis of independence.
Now suppose we would instead of $X^2$ use another quantity, like:
$$Q_1 =\sum(O-E)^2$$
or maybe
$$Q_2 = \sum|O-E|$$
to test the hypothesis of independence. Would that be "wrong" for some reason? Do we not use any of these (or other) alternatives because their distribution under the null hypothesis is unknown, as opposed to the null-distribution of $X^2$? That is to say, if we would generate the distribution of e.g. $Q_1$ under the null hypothesis of independence, could we than also use $Q_1$ to test for independence? Obviously, generating the exact distribution of e.g. $Q_1$ under independence, could be unfeasable for a large nr. of observations in the contingency table, but instead we could then draw a large sample (using e.g. r2dtable in R). However, maybe there exists another important reason why $X^2$ is simply a better or maybe even the best choice for testing independence. If so, then I would like to know that.
For all clarity, I'm not advocating any of the other quantities but would just like to know if theoretically these alternatives could be used too. Thanks for any guidance!