Suppose that a two-dimensional random variable $X$ has a covariance matrix given by
$$ \Sigma = \pmatrix {1 & -2\\ -2 & 4}$$
One of the three linear combinations below corresponds to the first principal component. Without performing an eigen-decomposition of the covariance matrix, identify which linear combination corresponds to the first principal component, and justify your answer.
Linear combination #1: $-0.447 X1 + 0.894 X2$
Linear combination #2: $-0.894 X1 - 0.447 X2$
Linear combination #3: $1.789 X1 + 1.789 X2$
I think I can safely eliminate #3 because the square of the coefficients needs to sum to 1. Both #1 and #2 have this property.
As the covariance between the two variables is negative, does this mean that the coefficients would have opposite signs i.e. #1?
Thanks
sum to 1
) is actually unnecessary: it is true if the "coefficients" are defined as eigenvector elements and may not be true otherwise. The actual answer is in your last statement: if the covariance is negative, i.e. the variables as vectors has >90 degrees angle between them from geometric point of view, then the 1st PC which is the line along the maximal joint variance should reflect that fact, by taking on coordinates of different sign. $\endgroup$