Here's how reconcile your table. For instance, look at the df=15 and $\alpha=0.05$, you see the critical value 0.446. Plug this thing into the formula, and look at the value of cumulative distribution function of Student t distribution with df=15-2. Here's the code in R:
> pt(0.446*sqrt(13/(1-0.446^2)),13)
[1] 0.9521751
You see that the right tail is about 5%, so, for two tailed test you get 10% in the tails - exactly what you asked with $\alpha=0.1$.
The formula in Wikipedia tell you that the expression is from Student t with n-2 degrees of freedom. Btw, this is how MATLAB calculates Spearman's critical value when there's a tie. Otherwise, it uses AS89 algo, to which I referred you in your other thread, but you didn't seem to like it :)
how to use this
. Isn't it thatt
to plug into Student's distribution withn-2
df? $\endgroup$