I am getting the "New factors levels not present in training data" error. But I checked the nlevels and class for every column in development as well as test data and they are the same. Any plausible explanation?
2 Answers
RF handles factors by one-hot encoding them. It makes one new dummy column for every level of the factor variable. When there are new or different factor levels in a scoring dataframe, bad things happen.
If the train and test existed together in the same data structure at the point that the factor was defined, there isn't a problem. When the test has its factor defined separately then you get issues.
library("randomForest")
# Fit an RF on a few numerics and a factor. Give test set a new level.
N <- 100
df <- data.frame(num1 = rnorm(N),
num2 = rnorm(N),
fac = sample(letters[1:4], N, TRUE),
y = rnorm(N),
stringsAsFactors = FALSE)
df[100, "fac"] <- "a suffusion of yellow"
df$fac <- as.factor(df$fac)
train <- df[1:50, ]
test <- df[51:100, ]
rf <- randomForest(y ~ ., data=train)
# This is fine, even though the "yellow" level doesn't exist in train, RF
# is aware that it is a valid factor level
predict(rf, test)
# This is not fine. The factor level is introduced and RF can't know of it
test$fac <- as.character(test$fac)
test[50, "fac"] <- "toyota corolla"
test$fac <- as.factor(test$fac)
predict(rf, test)
You can get around this issue by relevelling your scoring factors to match the training data.
# Can get around by relevelling the new factor. "toyota corolla" becomes NA
test$fac <- factor(test$fac, levels = levels(train$fac))
predict(rf, test)
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3$\begingroup$ Though this is certainly a workaround I have reservations about the soundness of this approach considering we expect training and test data to coexist entirely separately. $\endgroup$– TommyixiCommented Feb 6, 2020 at 19:41
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I just encountered the issue as well when using expand.grid()
to examine predictions of randomForest()
across various factor levels.
The issue is created by expand.grid()
setting stringsAsFactors = T
by default, which coerces strings to factors using the available levels of the data. This creates a problem when one is only using a subset of factor levels for predictions.
I fixed the issue by setting stringsAsFactors = F
which then allows randomForest()
to do the one hot encoding as the previous answer suggested.