Say I have two logistic models, the null model ($\omega_0$) and a model with one covariate ($\omega_1$). That is \begin{align} \omega_0: \quad \text{logit}(p_i) &= \beta_0 \\ \omega_1: \quad \text{logit}(p_i) &= \beta_0 + \beta_1 x_i \end{align} where $p_i = P(Y_i = 1)$ for some $Y_i \sim \text{Bernoulli}(p_i)$.
Shouldn't the Wald test for $\beta_1$ give the same result as the LRT for these nested models? I mean, aren't the null and the alternative hypothesis for these two tests the same? For the Wald test we have that \begin{equation} H_0: \beta_1 = 0 \quad vs. \quad H_1: \beta_1 \neq 0, \end{equation} and for the LRT we have the test statistic $D(\omega_0) - D(\omega_1)$ and the hypotheses \begin{align} &H_0: \omega_0 \quad &vs. \quad &H_1: \omega_1 \\ &H_0: \beta_1 = 0 \quad &vs. \quad &H_1: \beta_1 \neq 0 \end{align} In my analysis I've observed that the p-value of the Wald test is $0.04$ and the LRT gives a p-value of $0.07$. That is, with a cut-off of $0.05$, I arrive at different conclusions. I would expect that these two tests were asymptotically equivalent as I do have enough data.
So what is going on? Have I misunderstood the hypotheses in these two tests? Or is it just a coincidence that the two tests give p-values on either side of my cut-off level?
EDIT The vector of observations $\mathbf{y}$ and the corresponding covariate vector $\mathbf{x}$ both have $1.7 \times 10^6$ elements. Hence why I believe that the asymptotic results should apply.
However, I've found that there are a about 1800 cases where $y_i= 1$, and about 3000 cases where $x_i = 1$. Both $y_i$ and $x_i$ record very rare events that occur over a large time interval, hence why the vectors $\mathbf{y}$ and $\mathbf{x}$ have $1.7 \times 10^6$ elements. I realise that there are very few 1's compared to 0's in both $\mathbf{y}$ and $\mathbf{x}$. How does this effect the asymptotics?