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Im working on some school exercises and just cant figure out how to find answer:

First, I would like to regress $Y_i$ exclusively on the intercept and compute its residual $u_{Y_i}$. Secondly, I would like to regress $X_i$ exclusively on the intercept and compute its residual $u_{X_i}$. Based on that, I would like to derive least squares estimator without an intercept of a regression of $u_{Y_i}$ on $u_{X_i}$

I have tried to think about the first part as regressing $Y_i$ on a constant returning Y mean. However, I just cant figure out the rest. Many thanks for any hints.

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Since it's a self-study problem, I'm just giving a few hints. Let the regression line of Y on X be $Y=a+bX$.

  • That regression line goes through the point $(mean(X),mean(Y))$, therefore $mean(Y)=a+b·mean(X)$.
  • Residuals $u_{X_i}$ $u_{Y_i}$ from the first part of your problem are just $X_i-mean(X)$ and $Y_i-mean(Y)$.
  • By subtracting $Y=a+bX$ and $mean(Y)=a+b·mean(X)$ you can get $u_{Y_i}=a+b·u_{X_i}$ that is a regression line without intersect.
  • If you need to show that this is the least squares regression of $u_{Y_i}$ on $u_{X_i}$, you can use that the residuals here will be the same than in $Y=a+bX$.

Edit: "Regress $Y_i$ exclusively on the intercept", as I understand it, means fitting a model $Y=a$ (with $a$ constant). Adjusting this model using least squares yields just $Y=mean(Y)$.

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  • $\begingroup$ Hi @Pere thank your for that answer. I still cant figure out what it means to regress Y or X exclusively on the intercept. $\endgroup$
    – Mamba
    Commented May 29, 2017 at 4:37
  • $\begingroup$ @Mamba Added an edit. It might be understood in other ways, but understanding it as Y=constant makes the second part of the problem to make sense. $\endgroup$
    – Pere
    Commented May 29, 2017 at 8:18

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