3
$\begingroup$

I would like to know how the joint probability density function $p(b,r,\sigma^2)$ can be calculated for the following graph. Random variable $b$ is a latent binary variable, and random variable $\sigma^2$ is Inverse-Gamma. Random variable $r$ is observed and assumed Gaussian with two means ($\mu_0 = -1$ and $\mu_1 = 1$). In other words, $r$ can be generated from a Gaussian with mean = -1 or it can be generated from a Gaussian with mean 1.

$\sigma^2$ represents a common variance between the two Gaussians.

Bayes network

$\endgroup$
2
  • $\begingroup$ What happens when you try to factorize this graph? $\endgroup$ Commented Sep 26, 2018 at 17:58
  • $\begingroup$ So my understanding of probability density function is that in 1-D single variable $p(r)dr$ is the probability of sampling between $r$ and $r+dr$ where $r$ is a continuous variable as a binary variable, $b$ can equal 0 with probability $\pi$ and 1 with probability $1-\pi$ seems to me that $p(r,b,\sigma^2) = \left(\pi\delta_{\beta,0}+(1-\pi)\delta_{\beta,1}\right)p(r,\sigma^2)$ $\endgroup$ Commented Sep 26, 2018 at 18:02

1 Answer 1

1
$\begingroup$

This graph can be factorized according to the usual rules of Bayesian graphs:

$$ p(b,r,\sigma^2) = p(r|b,\sigma^2)p(b)p(\sigma^2) $$

If you want the marginal distribution $p(r, \sigma^2)$ (that is, averaged over possible $b$ outcomes), then you have the familiar mixture density:

$$ p(r,\sigma^2) = \Pr(b=1)p(r|b=1,\sigma^2)p(\sigma^2) + \Pr(b=0)p(r|b=0,\sigma^2)p(\sigma^2) $$

I'm abusing notation pretty badly here. I can clarify if any of it doesn't make sense.

$\endgroup$
8
  • $\begingroup$ what will $p(r|b,\sigma^2)$ be, when the means $\mu_0 = -1$ and $\mu_1 = 1$ are known and the variance unknown? $\endgroup$
    – fountain3
    Commented Jan 15, 2019 at 18:10
  • $\begingroup$ @fountain3 you are conditioning on $\sigma^2$, so it must be known. Just write $\sigma^2$. For $\mu$, you can write $\mu_b$, since $b$ is also known. $\endgroup$ Commented Jan 16, 2019 at 20:08
  • $\begingroup$ Terribly sorry I meant to write $p(r,\sigma^2|b)$. If $r$ is Gaussian, $\sigma^2$ is Gamma, and $b$ is binary, I need to get the expression for $p(r,\sigma^2|b)$. $\endgroup$
    – fountain3
    Commented Jan 17, 2019 at 8:06
  • $\begingroup$ @fountain3 just plug in $\mu_b$? $\endgroup$ Commented Jan 17, 2019 at 15:00
  • $\begingroup$ If I use the Normal-Gamma equation from wikipedia: en.wikipedia.org/wiki/Normal-gamma_distribution what should I use for the parameters of the Gamma part? $\endgroup$
    – fountain3
    Commented Jan 17, 2019 at 15:55

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.