2
$\begingroup$

I want to use a set of daily water quality data including 3 parameters in a Copula model. Somebody told me these data do not have a condition of a random variable to use in copula, and I should do some work on it (my guess is that it involves detrending the data).

Can anybody help me in finding methods to prepare the data to use in a copula method? I would appreciate if you can refer me to good journal papers or books.

$\endgroup$

1 Answer 1

2
$\begingroup$

Copulas are used for constructing joint distributions given the marginals. The parameters of the copula are used to model dependencies(correlation) between the marginals.

A good manuscript describing copulas is

http://www.math.uni-leipzig.de/~tschmidt/TSchmidt_Copulas.pdf

Unless you have some reason for transforming the observations from the marginals (maybe scaling or translating them), you do not need to "prepare" them to model them using a copula but maybe you have to take some time to choose properly the corresponding marginal distributions.

$\endgroup$
4
  • $\begingroup$ Thank you for the reply, but my data is a daily water quality data and it it has trend and seasonality therefore it can not be used directly in a copula model. I am sure about that because an expert told me that it is not a random data (I guess it is because that for different days of a year it has a trend). I want to know how can I prepare it to use in the model (I know it can be done by time series analysis and residuals but I don't know how). $\endgroup$
    – Fred
    Commented Dec 7, 2012 at 20:34
  • $\begingroup$ If the data are not random (according to that expert), then you cannot assign a stochastic model. My guess is that you need a different thing. Something like a nonlinear regression model or a time series. But more information about your data would help. $\endgroup$
    – Caesar
    Commented Dec 7, 2012 at 20:56
  • $\begingroup$ I attached the graph of my data (daily values of DO and T for 365 days of the year) in this link tinypic.com/r/2elyqrm/6 $\endgroup$
    – Fred
    Commented Dec 7, 2012 at 21:34
  • $\begingroup$ Regarding the second plot, it looks like a "seasonal trend" with a small variability between two consecutive days. Which is something expected but you can observe some small "noise". See for example the following simulation in R plot(25*sin(seq(1,365,1)*pi/365)+rnorm(365,0,1)). In the first plot the variability between two consecutive days is more apparent. Again, my guess is that what you need here is a nonlinear model that accounts for seasonality and other features present in your context. However, I do think that the data can be treated as random. $\endgroup$
    – Caesar
    Commented Dec 8, 2012 at 0:09

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.