3
$\begingroup$

I have three random variables, $X, Y, Z$. I know that

$$\log X - \log Y - \log Z = \log \frac{X}{YZ} \sim \mathcal{N}(0, \sigma^2)$$

How can I recover the distribution of $\frac{X}{YZ}$? Is it as simple as $e^{\mathcal{N}(0, \sigma^2)}$?

$\endgroup$

1 Answer 1

2
$\begingroup$

Let $W = \log X - \log Y - \log Z$.

So $W\sim N(0,\sigma^2)\,$.

What's the distribution of $\exp(W)$?

If you don't know what this is already, you can recover the density by simple change of variable.

If $Y=\phi(X)$, then:

$p_y(y) = p_x(\phi^{-1}(y)) ~ \left|\frac{d\phi^{-1}}{dy}\right|. $

Edit:

As the OP has now discerned, this means that $\exp(W)=\frac{X}{YZ}$ is $\text{lognormal}(0,\sigma^2)$.

$\endgroup$
4
  • $\begingroup$ So in this case, $\phi$ is $\exp$ and $E$ is $W$ and so $p_y(y) = p_W(\exp^{-1}(y)) |\frac{d \exp^{-1}}{dy}|$ ... ? $\endgroup$ Commented May 2, 2014 at 5:31
  • $\begingroup$ Well, $X$ is $W$ and $Y$ is $\exp(W)$. Further, you know what the inverse function of $\exp$ is already. $\endgroup$
    – Glen_b
    Commented May 2, 2014 at 5:49
  • $\begingroup$ Oh. So exp(W) is log-normally distributed then? $\endgroup$ Commented May 2, 2014 at 5:59
  • $\begingroup$ Yes. Wikipedia says: "a log-normal [...] distribution is a continuous probability distribution of a random variable whose logarithm is normally distributed." $\endgroup$
    – Glen_b
    Commented May 2, 2014 at 7:09

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.