All Questions
14 questions
0
votes
0
answers
194
views
Is there a function in R to give the lack of fit and pure error of an ANOVA completed on a half 2^k factorial with centre points?
I have a half fraction factorial experiment for four factors, meaning I have eight experiments that I conduct. I expect that some of the responses are quadratic and not linear, thus I included centre ...
1
vote
0
answers
36
views
Suggestion Needed about Design Experiment
As a part of my coursework, I'm supposed to be designing an experiment for an online cab service provider to understand the following:
Whether letting the cab driver know the drop location of the ...
- 123
0
votes
1
answer
151
views
Making sense of an actual equation obtained after Box-Cox transformation
I have recently performed and analysed an experiment and I am currently stuck on making sense of the outcome. Any help would be much appreciated.
The experiment consists of a simple DC voltage source ...
- 13
1
vote
0
answers
40
views
Variance of effects in $2^kr$ factorial design
I'm working through The Art of Computer Systems Performance Analysis, a statistics book focused on analyzing computer performance, and I don't follow the logic for computing the variation of effects ...
- 111
1
vote
0
answers
53
views
Is there value in assigning a dimension-specific weighting when calculating the main effect?
I've been looking into factorial designs and noticed an interesting property. Is this simply a mathematical trick or can we attribute some 'meaning' to it?
Say we have a $2^k$ design where k = 3 here....
- 11
0
votes
1
answer
84
views
How to study a fractional factorial design? [closed]
I wonder why a DoE/fractional factorial design isn't studied with the help of a linear mixed model? Or an Anova?
How to analyze it in general is e.g. given here.
Background: I will study several gas ...
- 3,493
1
vote
0
answers
26
views
"Incomplete Design" Problem: 2(between) x 2(within) x 2(within--but only in one between group!)
Problem:
I am trying to analyze an experiment with the design in the title:
2(between) x 2(within) x 2(within--but only manipulated in one group)
My initial hunch was to run two separate 2 (between)...
- 31
3
votes
0
answers
345
views
True replicates or nested data ANOVA - only one experimental unit per condition
I'm in materials science. I have a fractional factorial experiment. I am investigating the main effect of various treatments on a measured response. The exact details are probably not needed to ...
- 31
1
vote
0
answers
85
views
2 questions about fractional factorial design- efficiency and analysis
We're piloting a multiple variable testing program at my company. For starters, we're looking at a test with 3 factors (a, b, c), 2 levels (-1,+1) each. Based on research from several standard texts, ...
- 11
2
votes
0
answers
645
views
Control group in Incomplete Factorial Design
here, in title of Incomplete Factorial Design, it is written that
" it is actually impossible to implement a group that simultaneously has several levels of treatment factors and receives no ...
- 1,427
1
vote
0
answers
85
views
Fractional Factorial Design with Highest Resolution
In the book Design and Analysis of Experiments by Douglas C. Montgomery , it is written that
We usually like to employ fractional designs that have the highest ...
- 1,427
3
votes
1
answer
760
views
Fractional Factorial Design
In a $2^5$ design, it is believed that only the main effects $(A,B,C,D, E)$ and $AB,AC$ interaction effects are non-zero. I need to construct a fractional factorial with minimum number of runs which ...
- 1,427
1
vote
2
answers
2k
views
$2^{5-2}$ Design : Alias Structure
$2^{5-2}$ Design
Design Generators: $D=AB\quad E=AC$
Defining Relation: $I=ABD=ACE=BCDE$
$$\text{Aliases}$$
$$A=BD=CE=ABDE$$
$$B=AD=ABCE=CDE$$
$$C=ABCD=AE=BDE$$
$$D=AB=ACDE=BCE$$
$$E=ABDE=AC=BCD$$...
- 1,427
2
votes
1
answer
99
views
Alias Structure of one-fourth replicate of a $4^2$-Factorial Design with interaction $\text{A}{B}^3$ confounded
For finding the Alias of main effect A , i started as the following :
$\text{A}$$\times$ $\text{A}{B}^3$$=\text{A}^2\text{B}^3={(\text{A}^2\text{B}^3})^2=\text{A}^4\text{B}^6=\text{B}^2$(mod $4$)$={(\...
- 1,617