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1
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0
answers
39
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Does the R stats's resid(x,'type="normalized") functions produce the correct "normalized" mo... [closed]
ask this because the geepack does not "depend" or import from the stats package according to
https://cran.r-project.org/web/packages/geepack/geepack.pdf.
the stats package has the function residuals(fitted … object) and resid(fitted object).
residuals {stats} R Documentation
Extract Model Residuals
Description
residuals is a generic function which extracts model residuals from objects returned by modeling …
0
votes
0
answers
38
views
Resid vs Fitted plot for similar data on lme4 model looks vastly different on similar data. ...
I am using the same code to build the model for two different species but getting very different looking residual vs fitted plots and I am wondering why. …
5
votes
1
answer
2k
views
Adding an observation level random term messes up residuals vs fitted plot. Why?
The problem is: now my residuals plot (resid vs. fitted) has a clear pattern. If I delete that new "observation level random term" the plot looks good again.
Why? …
0
votes
1
answer
511
views
Residuals vs Fitted does not meet linear regression assumptions
I found a similar question (Residual vs Fitted) but (unless I am overthinking it) it does not apply to my issue since my data is not discrete data. … This is the residual vs fit graph I get:
And the QQ Plot:
From my understanding the Resid vs Fitted violates the assumptions of linear regression. From there I do now know what to do. …
0
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0
answers
28
views
Shall I further belive DHARMapackages whan dignosed?
However, When I finaly fitted a model with FUll variable . qqPlot(resid(Model)) tell me I got the right things but DHARMa's result told me I'm wrong. Shall I believe DHARMa Pakacages? … par(mfrow = c(1,2))
qqPlot(resid(M))
plot(resid(M) ~ fitted(M)); abline(h=0)
And pardon me I can't upload my dataset for your convinience because it will exceed the number of character. …
2
votes
2
answers
63
views
Resids vs fitted plot shows cyclical patterns. I have chosen 5 explanatory variables out of ...
Here is the resids vs fitted and qqplot of the model (obtained using 'plot(mod_och, type = 'residuals', series = 3)', the tails are heavy and residuals not normally distributed
I assumed the red line …
1
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0
answers
27
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Heteroscedasticity or not
The results agree with the suspicions, but clear groups are seen on the residual plot (resid vs. fitted) - please see the fig1. …
0
votes
0
answers
49
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Do these diagnostic plots show that my best model has good fit?
However, when I checked the diagnostic plots for the best model, they look as follows:
Should I be concerned about the fitted vs. resid plot? What could be causing that kind of dispersion? …
2
votes
1
answer
3k
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Correlation between standardized residuals and fitted values in a linear mixed effect model:...
hist(resid(M3))
qqnorm(resid(M3))
qqline(resid(M3))
Independence checks look good (?), for example here for facesex:
plot(data$facesex,resid(M3))
Heterogeneity check looks... well, hum. … plot(fitted(M3),resid(M3))
abline(h=0,col="grey")
lines(lowess(fitted(M3)[is.finite(fitted(M3))],resid(M3)[is.finite(fitted(M3))]),col="red")
The pattern is absent in M1 and M2. …
2
votes
0
answers
2k
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Diagonal pattern in fitted v. residuals plot for lmer multilevel model
With plot(fitted(model), resid(model)) I get the plot on the left below. … I get the following from model <- lm(time ~ gender + age + runs + friends, mydata) and plot(fitted(model), resid(model)):
So, the lm() seems okay in this regard. …
3
votes
1
answer
1k
views
Is it valid to use Anova (in R) to compare alternative multinomial log-linear models?
I am familiar with the idea of comparing alternative linear regression models using anova(model1,model2), for models fitted using lm() in R. … . df Resid. …
2
votes
0
answers
54
views
Is there a reason to plot residuals vs observed values rather than residuals vs fitted values? [duplicate]
.fitted, y = .resid)) +
geom_point() +
geom_smooth(se = FALSE, col = "red") + #Adds the line of fit
geom_hline(yintercept = 0, linetype = 2) + #Adds the horizontal dashed line
labs(x ="Fitted … Values", y ="Residuals", title = "Residual vs Fitted") +
theme_bw()
##Residuals vs Petal.Length (what my prof wants)
ggplot(data = d, aes(x = Petal.Length, y = .resid)) +
geom_point() +
geom_smooth …
0
votes
0
answers
11
views
How might I go about analyzing the affect that the number of attempts of something has on th...
Passing this into a linear model with a log-log transform, the qqplot and histogram looked pretty normal but the resid vs fitted was definitely off, but I don't know exactly what causes the behavior (pictured …
5
votes
1
answer
2k
views
What resolution should I be using for residuals vs fitted values plot from a linear regression?
It appears to shows residuals that are correlated with the fitted values:
library(ggplot2)
df_lm_longitude <- ggplot2::fortify(lm_longitude)
ggplot(df_lm_longitude, aes(.fitted, .resid)) + geom_point … () + stat_smooth()
But change the scale of the y axis, and residuals vs fitted values plot looks perfect:
ggplot(df_lm_longitude, aes(.fitted, .resid)) + geom_point() + stat_smooth() + ylim(-0.01, …
4
votes
2
answers
3k
views
Why are Pearsons residuals from a Poisson regression so large?
I ran this Poisson regression:
library(ggplot2)
glm_diamonds <- glm(price ~ carat, family = "poisson", data=diamonds)
I then saved the Pearsons residuals and fitted values from the model:
resid <- … resid(glm_diamonds, type = "pearson")
fitted <- fitted(glm_diamonds)
df <- data.frame(resid, fitted)
I then plotted the Pearsons residuals against fitted values:
ggplot(df, aes(fitted, resid)) + geom_point …