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The expected value of a random variable is a weighted average of all possible values a random variable can take on, with the weights equal to the probability of taking on that value.

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Does $\max_{x\in X}E[Y\mid X=x] = \max_{P_X}\sum_{x\in X}P_X(x)E[Y\mid X=x]$?

Does this expression hold? $$\max_{x\in X}E[Y\mid X=x] = \max_{P_X}\sum_{x\in X} P_X(x)E[Y\mid X=x]$$ Left side says: max over all available $x$ for the expected value of $Y$ given $X=x$. Right side …
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