Search Results
Search type | Search syntax |
---|---|
Tags | [tag] |
Exact | "words here" |
Author |
user:1234 user:me (yours) |
Score |
score:3 (3+) score:0 (none) |
Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
Views | views:250 |
Code | code:"if (foo != bar)" |
Sections |
title:apples body:"apples oranges" |
URL | url:"*.example.com" |
Saves | in:saves |
Status |
closed:yes duplicate:no migrated:no wiki:no |
Types |
is:question is:answer |
Exclude |
-[tag] -apples |
For more details on advanced search visit our help page |
Principal component analysis (PCA) is a linear dimensionality reduction technique. It reduces a multivariate dataset to a smaller set of constructed variables preserving as much information (as much variance) as possible. These variables, called principal components, are linear combinations of the input variables.
0
votes
How to derive the three matrices of SVD from eigenvalue decomposition in Kernel PCA?
Based on @whuber's answer it's simply:
$$
\mathbf{V}=\mathbf{X^TU\Sigma^{-1}}
$$
1
vote
1
answer
101
views
How to derive the three matrices of SVD from eigenvalue decomposition in Kernel PCA?
Kernel PCA is usually done via eigenvalue decomposition of the Kernel Matrix $\mathbf{K}$ and standard PCA via SVD of the input $\mathbf{X}$. … In standard PCA as far as I know we can derive $\mathbf{S}$ and $\mathbf{U}$ via two eigenvalue decompositions, of the Gram and Covariance/Correlation matrices:
$$
\begin{array}{c}
X=U\Sigma V^T\\
C=\ …