Timeline for Distribution of sum of negative binomial parametrized with varying mean and constant aggregation parameter
Current License: CC BY-SA 3.0
13 events
| when toggle format | what | by | license | comment | |
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| Dec 25, 2015 at 8:18 | answer | added | MarcG | timeline score: 2 | |
| S Oct 9, 2015 at 21:48 | history | suggested | MarcG | CC BY-SA 3.0 |
I precise the question because the previous formulation was not enough precise
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| Oct 9, 2015 at 21:30 | comment | added | Silverfish | @MarcG You appear to have created two separate accounts! Please see this help page so you can merge them again. This will mean you can instantly edit your own posts rather than wait for your edits to get approval. | |
| Oct 9, 2015 at 21:19 | review | Suggested edits | |||
| S Oct 9, 2015 at 21:48 | |||||
| Aug 2, 2015 at 7:56 | history | edited | MarcG |
Add a new tag
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| Aug 2, 2015 at 1:03 | comment | added | Glen_b |
Please add the self-study tag, read its tag-wiki and modify your question to follow the guidelines on asking such questions. (In particular, you'll need to clearly identify what you've done to solve the problem yourself, and indicate the specific help you need at the point you struck difficulty.)
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| Aug 2, 2015 at 1:00 | comment | added | Glen_b | Xi'an is correct -- now you've already done it all yourself apart from the final step of writing the final line (the value for the mu-parameter of the sum). If you know how to switch between parameterizations (as you just did), and you know how to write the distribution of $\sum X_i$ in one form, you can write it in the other form. $\sum r_i$ is a single number, (use $R=\sum r_i$ if it helps); write what the $\mu$ parameter must be in terms of $p$ and $\sum r_i$ (or $p$ and $R$ if it's easier that way; just convert back at the end). | |
| Aug 1, 2015 at 17:08 | comment | added | Xi'an | @MarcG: I think Glen_b is trying to help you find the solution by yourself: if you know how to switch between both parameterisations then the solution is contained in the question. | |
| Aug 1, 2015 at 13:40 | comment | added | MarcG | In this parametrization, p = r/(r+µ) so µ=(r/p)-r=r (1/p - 1)=r (1-p)/p | |
| Aug 1, 2015 at 8:25 | history | edited | Andy | CC BY-SA 3.0 |
added 17 characters in body
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| Aug 1, 2015 at 7:43 | comment | added | Glen_b | how is $\mu$ related to $r$ and $p$ in this perameterization? | |
| Aug 1, 2015 at 7:27 | review | First posts | |||
| Aug 1, 2015 at 8:25 | |||||
| Aug 1, 2015 at 7:22 | history | asked | MarcG | CC BY-SA 3.0 |