1
$\begingroup$

Suppose the following two stage regression (estimated using OLS).

Stage 1: $y_i = \alpha + \beta X_i + u_i$

Stage 2: $u_i = \gamma + \delta Z_i + v_i$,

where $y_i$, $X_i$, and $Z_i$ are random variables. $i$ denotes observation $i$. $u_i$ and $v_i$ are residuals and $\alpha$, $\beta$, $\gamma$, and $\delta$ are estimated coefficients.

I have two questions:

(i) Is the standard error of $\delta$ correct. If not, what is the reason?

(ii) How can I get the correct standard error?

Thank you a lot!

$\endgroup$
6
  • $\begingroup$ I want to generate a measure for a specific phenomena (represented by the residuals $u_i$). Finally, I want to research the relationship between this measure and a third variable $Z_i$. $\endgroup$
    – Efissi
    Commented Feb 16, 2016 at 20:59
  • $\begingroup$ Thank you a lot for your help! Unfortunately, I don't see the parallel. In your example, there is measurement error in an independent variable. How is that connected to my question? $\endgroup$
    – Efissi
    Commented Feb 16, 2016 at 21:07
  • $\begingroup$ Related: stats.stackexchange.com/questions/127001/… $\endgroup$
    – Tim
    Commented Feb 16, 2016 at 21:29
  • $\begingroup$ I have seen that; unfortunately, there is no fully insightful discussion of my two raised questions. $\endgroup$
    – Efissi
    Commented Feb 16, 2016 at 21:34
  • $\begingroup$ Your questions are not very clear. What do you mean is the standard error of $\delta$ "correct"? Do you mean the standard error for an estimator of $\delta$? If so it depends on you're estimating it. Also, why shouldn't we view this as a one stage model with $y_i = \alpha + \gamma + \beta x_i + \delta z_i + u_i + v_i$? $\endgroup$
    – dsaxton
    Commented Feb 22, 2016 at 14:27

1 Answer 1

2
$\begingroup$

(sorry, this is not a full fledged answer but just my thoughts about it in the hope to let the discussion start again)

I am going through the same issue right now. I think what Efissi means with "is the sd of $\delta$ correct?" is exactly what @dsaxton commented, i.e., if the estimates and the confidence intervals of the coefficients calculated via the two-stage model are the same (up to some reparametrization) as in the one-stage model.

My personal view is yes, as long as $X$ and $Z$ are independent from each other. The reason is, if you imagine your data as a cloud in a multidimensional space and you do a (univariate) OLS linear regression w.r.t. $X$, you are projecting the data to the (unidimensional) subspace $X$, but you are not applying any transformation in the rest of the hyperplane. Thus any relationship to any other covariates should remain unchanged.

Mathematically, substituting the model for $u_i$ in the model for $y_i$:

\begin{split} y_i &= \alpha + \beta X_i + u_i =\\ &= \alpha + \beta X_i + (\gamma + \delta Z_i + v_i) =\\ &= (\alpha + \gamma) + \beta X_i + \delta Z_i + v_i \end{split}

thus, in particular, the $\delta$ should have the same properties in the two-stage model as well as in the one-stage model $Y \sim X + Z$.

Does it make sense or am I missing something? In particular, is the independence condition necessary?

UPDATE

A short check with real data:

dat <- mtcars

> lm1 <- lm(mpg ~ hp + qsec, data=dat)
> summary(lm1)$coef
               Estimate  Std. Error   t value     Pr(>|t|)
(Intercept) 48.32370517 11.10330633  4.352191 1.526469e-04
hp          -0.08459304  0.01393281 -6.071497 1.309333e-06
qsec        -0.88657962  0.53458538 -1.658443 1.080072e-01


> lm2a <- lm(mpg ~ hp, data=dat)
> summary(lm2a)$coef
              Estimate  Std. Error   t value     Pr(>|t|)
(Intercept) 30.09886054  1.6339210 18.421246 6.642736e-18
hp          -0.06822828  0.0101193 -6.742389 1.787835e-07

> lm2b <- lm(lm2a$residuals ~ dat$qsec)
> summary(lm2b)$coef
              Estimate Std. Error   t value  Pr(>|t|)
(Intercept)  7.8871608  6.8116279  1.157897 0.2560418
dat$qsec    -0.4418887  0.3797911 -1.163505 0.253795

For comparison:

> summary(lm(hp ~ qsec, data=dat))$coef
             Estimate Std. Error   t value     Pr(>|t|)
(Intercept) 631.70375  88.699525  7.121839 6.382739e-08
qsec        -27.17368   4.945556 -5.494565 5.766253e-06

> summary(lm(qsec ~ hp, data=dat))$coef
               Estimate  Std. Error   t value     Pr(>|t|)
(Intercept) 20.55635402 0.542424287 37.897186 6.728254e-27
hp          -0.01845831 0.003359377 -5.494565 5.766253e-06

Nevertheless, a simulation with artificially created independent $X$ and $Z$ delivered exactly the same values in the two models. Thus, the difference of estimates could be interpreted as some measure of dependence or correlation between the covariates, but honestly I don't know how to quantify and/or use it.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.