Let's consider a finite mixture:
$$f(x) = \sum_{i=1}^{N}w_{i}p_{i}\left(x\right)$$
where:
- $N$ is the number of mixed distributions
- $\left\{p_{1},\dots, p_{N}\right\}$ is a finite set of one-dimensional probability density functions in $\mathbb{R}^{+}$
- $\left\{w_{1},\dots, w_{N}\right\}$ is a finite set of associated weights
Now, let's say that $f$ is a mixture over a parametric family, where distributions are parameterized by a set of $\left\{\alpha^{1},\dots, \alpha^{n}\right\}$ parameters (where the upper index is just an index and not an exponentiation):
$$f(x) = \sum_{i=1}^{N}w_{i}p\left(x;\alpha^{1}_{i},\dots, \alpha^{n}_{i}\right)$$
And let's say that these parameters can be themselves parameterized by a single parameter:
$$f(x, \lambda) = \sum_{i=1}^{N}w_{i}p_{i}\left(x;\alpha^{1}_{i}\left(\lambda\right),\dots, \alpha^{n}_{i}\left(\lambda\right)\right)$$
The question is: is there a distribution $p$ such that $f$ itself would be a member of the parametric family:
$$p\left(x;\alpha^{1}_{0},\dots, \alpha^{n}_{0}\right) = \sum_{i=1}^{N}w_{i}p\left(x;\alpha^{1}_{i}\left(\lambda\right),\dots, \alpha^{n}_{i}\left(\lambda\right)\right)$$
In other words, given:
- a mixture size $N$
- a parameter $\lambda$
- a set of parameters $\left\{\alpha^{1}_{0},\dots, \alpha^{n}_{0}\right\}$
would there be a distribution $p$ such that it would be possible to find a set of weights $w_{i} \neq 0$ and a set of set of parameters $\left\{\left\{\alpha^{1}_{1}\left(\lambda\right),\dots, \alpha^{n}_{1}\left(\lambda\right)\right\}, \dots, \left\{\alpha^{1}_{N}\left(\lambda\right),\dots, \alpha^{n}_{N}\left(\lambda\right)\right\}\right\}$ so that the equality above holds.
For example if $p$ is a normal distribution, can one find a set of $N$ normal distributions and their weights parameterized by $\lambda$ so that the mixture is itself a normal distribution?