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In the Definition 3.4.1 of Pearl's causal inference book (Primer), the second rule for the front door criterion is "There is no backdoor path from $X$ to $Z$". But from my understanding, there EXISTS one backdoor path from $X$ to $Z$: $X \leftarrow U \rightarrow Y \leftarrow Z$. And this backdoor path is blocked by the collider $Y$.

Can anyone help me understand this rule? Thank you.

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I can understand your confusion. In the Front-Door Criteria of Definition 3.4.1, the original text for #2 read, "There is no unblocked path from $X$ to $Z$." The book's errata changed that to "There is no backdoor path from $X$ to $Z$." I admit it's a bit confusing either way: Pearl was a little more careful in his 2009 book Causality: Models, Reasoning, and Inference, 2nd Ed. On page 82 of that book, Definition 3.3.3 (Front-Door), the second item on the list reads: "there is no unblocked back-door path from $X$ to $Z;...$"

It certainly is the case that $Y$ satisfies the Backdoor Criterion (Def. 3.3.1 on page 61) relative to $(X,Z).$ This is what enables Pearl to say, in the derivation of the Front-Door criterion, that

$$P(z|\operatorname{do}(x))=P(z|x).$$

That plus Def. 3.4.1, #1 and #3 are sufficient to enable the Front-Door procedure to work.

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  • $\begingroup$ Thank you Adrian! The requirement "there is no unblocked back-door path from 𝑋 to 𝑍" holds for the lung cancer example, since the only back-door path from 𝑋 to 𝑍 is blocked by collider Y. Because the backdoor from X to Z is blocked by just a collider, we can have P(z|do(x)) = P(z|x). Please correct me if my current understanding about the second rule is not correct. $\endgroup$
    – bcxiao
    Commented May 19, 2023 at 17:32
  • $\begingroup$ You've got it, I think! $\endgroup$ Commented May 19, 2023 at 18:21

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