7
$\begingroup$

I am trying to study predictors of companies' pollution output of some specific chemicals. The data I am using have many 0's (i.e., the company did not pollute at all with those chemicals) and then are continuous with a long right tail. I have seen others model this data by logging the dependent variable after adding 1. My sense is that this is wrong, but I don't understand why. Could someone explain? This approach is much simpler than what I think I should be doing - using zero-inflated two-part models for semi-continuous data - so I'd be thrilled if it turned out simply adding 1 and logging is right.

Second, I have found a Stata ado file to run zero-inflated two-part models for semi-continuous data. Is there a way to incorporate fixed effects into this type of model?

$\endgroup$

2 Answers 2

1
$\begingroup$

Not sure about Stata, but R can run zero-inflated models with fixed effects. Check out, for example, the gamlss package and zeroinfl() from the pscl package.

$\endgroup$
4
$\begingroup$
  1. Disadvantages of $\ln(0+c)$:

    • $c=1$ is arbitrary. Often the value of $c$ changes estimates, so you need to conduct a grid search for the "optimal" result and justify that choice in the end
    • Zero mass may respond differently to covariates (extensive vs. intensive margin may have different DGPs)
    • Retransformation back to natural scale problem is worse at the low end if you want to predict $y$
    • Sometimes works poorly. See Duan, N., W.G. Manning, et al. “A Comparison of Alternative Models for the Demand for Medical Care,” Journal of Business and Economics Statistics, 1:115-126, 1983 for some examples. (gated JSTOR link, RAND working paper link).
  2. There's no panel version of tpm. I would try using dummies and clustering on the panel id if computationally possible. I might also give xtpoisson, fe robust or xtpqml (a user-written wrapper) a whirl, justifying it as Quasi-MLE, which has performed well in CS simulations even when the number of zeros is large.

$\endgroup$
1
  • $\begingroup$ xtnbreg is good to note as well. I've estimated good fitting models with up to 65% zero observations using the negative binomial. $\endgroup$
    – Andy W
    Commented Feb 20, 2014 at 18:50

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.