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I have the following irregularly spaced time series. enter image description here

The related autocorrelogram is: enter image description here

and I run the following tests:

> adf.test(x)

Augmented Dickey-Fuller Test

data:  x
Dickey-Fuller = -70, Lag order = 70, p-value = 0.01
alternative hypothesis: stationary

Warning message:
In adf.test(x) : p-value smaller than printed p-value


> kpss.test(x)

KPSS Test for Level Stationarity

data:  x
KPSS Level = 30, Truncation lag parameter = 100, p-value = 0.01

Warning message:
In kpss.test(x) : p-value smaller than printed p-value


> Box.test(x, type = "Ljung-Box")

Box-Ljung test

data:  x
X-squared = 20000, df = 1, p-value <2e-16

How can this time series be stationary? I suppose problems arise because my time series is irregularly spaced. In this case, there exist methods to assess stationarity with irregularly spaced time series?

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1 Answer 1

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While the data does not appear to have a unit root (which is also confirmed by the ADF test results), KPSS test rejects stationarity. Recall that the null hypothesis of KPSS is stationarity (in contrary to the ADF test). That is quite intuitive when you look at the graph.

Edit (to respond to edited post)
Of course, irregular spacing will be a problem. My answer only addresses the apparently incorrect interpretation of the KPSS test results.

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  • $\begingroup$ Whoaaa ok! I wasn't aware that the null hypothesis of KPSS is stationarity! That makes sense! $\endgroup$ Commented Apr 5, 2016 at 10:31
  • $\begingroup$ Are these tests somewhat robust against the extreme outliers and the extremely skewed distribution shown in the first figure? $\endgroup$
    – Michael M
    Commented Apr 5, 2016 at 12:28
  • $\begingroup$ @MichaelM, Sorry, I don't know the answer. $\endgroup$ Commented Apr 5, 2016 at 13:12
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    $\begingroup$ @MichaelM, outliers will bias the ADF test towards rejecting the null of a unit root. The intuition is that the series will seem more mean reverting. $\endgroup$
    – Plissken
    Commented Apr 5, 2016 at 17:16
  • $\begingroup$ Thank you@Plissken. The series looks like count data, so probably the test for stationarity is the least problem here. $\endgroup$
    – Michael M
    Commented Apr 5, 2016 at 17:55

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