Let $Z_{1},\ldots, Z_{n}$ random variables i.i.d with symmetric continuous distribution in $\theta$.
We consider hypothesis test $$\begin{array}{rcl} H_{0}: && \theta=\theta_{0} \\ H_{a}: && \theta>\theta_{0} \\ \end{array}$$
Let $T_{\theta}$ be a statistic, and let $$\alpha=\mathsf{P}(T_{\theta_{0}}\geq c | H_{0} \mbox{ true})$$ is significance level, that is, reject the null hypothesis if $T_{\theta_{0}}(Z)\geq c$.
My question: What is the power of $T$?
Remark: We remember that
Definition. The power of a hypothesis test is the probability of making the correct decision if the alternative hypothesis is true. That is, the power of a hypothesis test is the probability of rejecting the null hypothesis $H_{0}$ when the alternative hypothesis $H_{a}$ is the hypothesis that is true.
I know that $$\textrm{power}=1-\mathsf{P}(T_{\theta_{a}}\geq k|H_{a}\mbox{ is true})=\mathsf{P}(T_{\theta_{a}}\leq k|H_{a}\mbox{ is true})$$ where $k$ depend of $c$. I do not understand as from $ c $ I can get $ k $ in general. For example, for statistic $$T_{\theta}=\frac{\sqrt{n}(\overline{Z}-\theta)}{s}$$ It is easy to see the dependency of $ c $ (see this link). But it is not easy for the case of the signed statistic $$B=\sum_{i=1}^{n}\psi(Z_{i}-\theta) \quad \mbox{ where } \quad \psi(x):=\left\{\begin{array}{ll} 1 & x>0\\ 0 & x\leq 0 \end{array} \right.$$ or the Wilcoxon signed rank statistic $$W^{+}=\sum_{i=1}^{n}\psi(Z_{i}-\theta)R^{+}_{i}$$ where $R^{+}=(R^{+}_{1},\ldots,R^{+}_{n})$ is the rank vector of $|Z_{1}|,\ldots,|Z_{n}|$. I really have not been able to see that dependence in these cases.
