In the section on linear regressions $\mathbf{Y} = \mathbb{X}\beta + \epsilon$, my textbook represents the design matrix as
$\mathbb{X} = \begin{bmatrix} \mathbf{x}_{1}^T \\ \vdots \\ \mathbf{x}_{n}^T \\ \end{bmatrix} = \begin{bmatrix} x_{11} & \dots & x_{1p} \\ \vdots \\ x_{n1} & \dots & x_{np} \end{bmatrix} \in \mathbb{R}^{n \times p}$
I realise that the $T$ in the vector means transpose, but since the transpose operator is on each individual element $\mathbf{x}$ rather than the entire vector itself, what is its function here? Comparing the vector and the matrix, it seems like the transpose operator is doing nothing here; the matrix looks as it would were the $T$ not present. Or am I misunderstanding something?
I would greatly appreciate it if people could please take the time to clarify this.