I refer to What follows if we fail to reject the null hypothesis? to explain that, in hypothesis testing, the objective is to show that your data 'rejects' $H_0$ and 'supports $H_1$.
You want to 'show' that '... whether a white candidate (for a job) is chosen more often than an equally qualified minority candidate'.
So if $\pi$ is the fraction of white candidates that are chosen then $H_1: \pi > 0.5$ versus $H_0: \pi = 0.5$.
This is done before you have seen the data. This was also argued by @Greg Snow
If you draw a random sample of size $n$ ($n$ large enough), then for each sample $s$ you observe a fraction $p_s$ in that sample. Obviously, in another sample you will observe another $p_s$ so this 'sample fraction' changes from sample to sample and is therefore a random variable. If $n$ is large enough, then this random variable 'sample fraction' will be normally distributed with mean the population fraction $\pi$ and standard deviation $\sqrt{\pi(1-\pi)/n}$.
So if you choose a significance level (e.g.) $\alpha=0.05$ then you find that $P(p_s \ge \pi + 1.645 \sqrt{\pi(1-\pi)/n})=0.05$. So the rejection region with $\pi=0.5$ (if $H_0$ is true) and e.g. $n=100$ would be $p_s \ge 0.5+1.645\sqrt{0.25/100}$ or $p_s \ge 0.58$.
All this reasoning is done without looking at the data, you only have to fix $\alpha$ and the sample size $n$.
Only in the final step you look at your specific sample and in your your sample the fraction of white that are chosen is 0.54. Si the value of $p_s$ for your sample ($\bar{p}_s=0.54$) is not in the critical region ($p_s \ge 0.58$).
Note that this decision depends on the sample size and on the $\alpha$.
So it is very important to distinguish between the population
fraction $\pi$ which is the one you use in your hypothesis and the
outcome of your specific sample fraction $\bar{p}_s$. It is also important to distinguish the fraction of your sample $\bar{p}_s$
(which is only one number, namely the fraction in the sample that you
have) from the outcome of any possible sample of the same size
, this latter is a random variable $p_s$ because its value depends on
the sample, so $p_s$ is not one value but a random variable (thus a
distribution).