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I am running mixed effects models with percentage data.

I run my model using a gaussian distribution approach. AIC=-258, my conditional and marginal pseudo-R squares were 0.33 and 0.11 respectively (very good!). I realized that I should model it using a binomial distribution because I have percentages. Now, the results are pretty similar, but my AIC=2386 is worse and pseudo-R squares diminished a lot (0.07 conditional and 0.02 marginal).

Is this saying that the gaussian approach fits the data better and therefore I should use it preferentially? How could I justify it?

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  • $\begingroup$ . Now, the results are pretty similar, but my AIC=2386 is worse and pseudo-R squares diminished a lot (0.07 conditional and 0.02 marginal. If AIC becomes worse, How do you justify binomial distribution and how can you say that percentage data makes a binomial data - Yes or No data. is that intuitive or irrational approach ! $\endgroup$
    – user10619
    Commented Jul 10, 2018 at 5:26
  • $\begingroup$ Here is a somewhat similar question: stats.stackexchange.com/questions/142338/… $\endgroup$ Commented Jul 11, 2018 at 13:47
  • $\begingroup$ I do not find any relevance of the specified quuestion or answer to the present lssue $\endgroup$
    – user10619
    Commented Jul 12, 2018 at 0:07

1 Answer 1

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There are a bunch of issues here

About the decision what to do - in doubt, I would simply go for the data-generating model, i.e. in case of k/n for a binomial. Check the model fit, e.g. with DHARMa, and with k/n binomial, you also have to check for overdispersion.

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  • $\begingroup$ Thank you Florian Hartig for your answer. I have k/n proportions, but I checked for overdispersion, as you suggested and it is very high. I will have to add an observation level random effect to deal with it. $\endgroup$
    – Charly
    Commented May 18, 2018 at 19:15
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    $\begingroup$ @Charly, you should consider the community's assessment of the quality of these two answers (as expressed by the vote totals). I would urge you to be cautious about acting on Subhash's advice. You may also want to switch which answer is accepted. $\endgroup$ Commented May 24, 2018 at 14:23

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