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I am learning coupla. I read that we need to transform the margins to the uniform distribution in order to get the copula data. Is that correct? Also, I read that to obtain copula data, we can transformed the margins distribution non-parametically using their empirical cumulative distribution function. I wonder is that correct? or do I miss-understand the idea of obtaining the copula data? If this is correct, then why copula oly works on standard uniform distribution?

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Q: why copula oly works on standard uniform distribution

Consider some arbitrary distribution, let's say log normal for the sake of discussion. Picture the shape of the density function ($f(x)$). It is roughly bell shaped with positive skew. Now imagine taking a sample ($s$) from this distribution. You would expect it, on average, to have a histogram of roughly the same shape.

Now here comes the tricky part...

Consider the cumulative density function of the same distribution ($F(x)$).

$F(x)$ takes a value from your sample space, and returns the probability of observing a value that is less than or equal to x. Consider the shape of $F(x)$. Moving along the x-axis from left to right, it starts with a flat section, then gets very steep, then flattens out again. The flat sections indicate that your sample is not expected to contain many observations in that range, because changing the x value by a bit, doesn't change the probability very much. The steep section indicates that your sample is expected to contain many observations in that range, because changing the x value, changes the probability a lot.

Now consider what happens if you feed your sample into $F(x)$. What would the output look like? Remember, the output is a bunch of probabilities. So what distribution would your output have? It would have a uniform distribution, because most of your sample is from the steep section, which gets spread out on the y-axis because the function is steep. And the few observations from the flat section get compressed on the y axis because the function is flat. So parts of your x axis that are tightly clustered become spread out on the y axis, and parts of your x axis that are spread out, get more clustered on the y axis. The result is that if you feed data from any distribution through its corresponding cdf, you will be left with uniformly distributed data.

But this is boring with uni-variate data. It is more interesting with multi-variate data. A coplula is basically doing this same exercise for multivariate data. It describes how high probabilities from variable 1, correlate with high probabilities from variable 2, for example.

I read that we need to transform the margins to the uniform distribution in order to get the copula data

First let's get a definition clear.

Marginal distribution: A distribution of some data that comes from a multivariate distribution, but you ignore all the other variables and only consider the distribution of the variable in question.

So a copula is what you get when you take a multivariate distribution and factor out all the marginal distributions. What you are left with is a multivariate uniform distribution, for the reasons I mentioned above.

we can transformed the margins distribution non-parametically using their empirical cumulative distribution function. I wonder is that correct?

You can get an empirical copula by obtaining the ranks for each variable in each observation. Convert the ranks to numbers between 0 and 1, and you are done. See the following R demo

library(MASS)

mu = seq(0.1, 0.2, length.out = 10)
Sigma = matrix(0.8, ncol = 10, nrow = 10)
diag(Sigma) = seq(1,1,length.out = 10)
x = mvrnorm(n = 100000, mu = mu, Sigma = Sigma)

marg1 = x[,1]
plot(density(marg1, bw = "SJ"))

ranks = sapply(1:10, function(i){rank(x[,i])}) / 100000

marg_rank_1 = ranks[,1]
plot(density(marg_rank_1, bw = "SJ"))

plot(ranks[,1],ranks[,2], cex = 0.5, col = rgb(0,0,0,alpha = 50,maxColorValue = 255), pch = 16)

Here I have shown the distribution of the first variable, which is normal. However, the ranks are uniform. The ranks in this demo, is your copula data.

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  • $\begingroup$ this is such a great explanation, thank you. could you also answer this regarding the ranking/discretization procedure for estimating empirical copula: stats.stackexchange.com/questions/485081/… $\endgroup$
    – develarist
    Commented Aug 29, 2020 at 12:23

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