# How to prove $P(a \geq b +c) \leq P(a \geq b) + P(c \leq 0)?$

How to prove $$P(a\geq b+c)\leq P(a\geq b)+P(c\leq0)?$$

Thanks.

• $a\ge b+c$ happens when either (i) $a\ge b+c$ and $c\ge 0$ or (ii) $a\ge b+c$ and $c\le 0$, which are incompatible events. – Xi'an Apr 9 at 7:51

The critical relation is: $$P(a\geq b+c)\leq P(a\geq b \cup c \leq 0)$$ because RHS is more general, i.e. when it doesn't happen, we have $$a0$$, in which we cannot have $$a\geq b+c$$.
Then, we just apply set rules: $$P(a\geq b+c)\leq P(a\geq b)+P(c\leq 0)-P(a\leq b\cap c\leq 0)\leq P(a\geq b)+P(c\leq 0)$$