1
$\begingroup$

Below is a Directed Acyclic Graph (Fig.a). From this figure, it is said that:

$E$ and $F$ are conditionally independent given $C$ and $D$.

I am confused about it. Let's assume the causal relationships among $A \sim F$ in Fig.a are:

\begin{cases}C=A-B\\E=C+D\\F=C\times D\end{cases}

Then if we know the value of $C$ and $D$, $E$ and $F$ are determined. In addtion, since the equation can be written as: $E=D/F+D$, then $E$ and $F$ are dependent given $D$.

Why they are conditionally independent given $C$ and $D$?

I find that in this post, a paper from Elwert F. and Winship C. (2014) is recommended. I read it (though not fully understand), and think that the relationship among $C, D, E, F$ is a combination of Figure 3 & 4 (attached below as Fig.b) in their paper:

  • from the view of Figure 3, $E$ and $F$ are associated by common cause (i.e., $C$ and $D$);
  • from the view of Figure 4, $E$ is the collider of $C$ and $D$; $F$ is the collider of $C$ and $D$.

Fig.a Fig.b

$\endgroup$
2
  • $\begingroup$ Your question seems to come down to "why are two constants independent?" Although intuition may be of little help, it's a simple matter to apply the definition of independence to verify this is the case. $\endgroup$
    – whuber
    Commented Jun 25, 2019 at 14:36
  • $\begingroup$ I changed $A$ ~ $F$ to $A \sim F.$ That is standard usage. $\qquad$ $\endgroup$ Commented Jun 25, 2019 at 21:39

1 Answer 1

2
$\begingroup$

When two random variables $A$ and $B$ are independent, that means we cannot learn anything about $A$ by observing $B$, or vice versa. Whatever we knew about $A$ before observing $B$, we know nothing more afterwards.

In your graph, $E$ and $F$ are related through common causes. So, in general, observing $E$ can tell us something about what values $F$ is likely to take. More specifically, $E$ gives us information about $C$ and $D$, and from that information we can make guesses about $D$. So $E$ tells us something about $F$ only because it tells us about $C$ and $D$.

But now suppose we actually get to observe $C$ and $D$. We already know their values, so there is nothing more we can learn about them by observing $E$. This means that $E$ now also can tell us nothing more about $F$. $E$ was only informative about $F$ when it could tell us something about $C$ and $D$.

In your example, it is true that you can work out the value of $E$ from $F$. And indeed, if you know $D$ and $F$ but you don't know $C$ (for instance), then you have to rely on $F$ to figure out the value of $E$ (using $E=D/F+D$). But if you're also given $C$, then you can work out $E$ without having to know $F$ (using $E=C+D$). Thus, when $C$ and $D$ are given, there is no more information about $E$ in $F$ that you couldn't already get from $C$ and $D$.

Note also that the statement specifically says that $E$ and $F$ are conditionally independent given both $C$ and $D$. Given only $C$ or $D$, they are still mutually dependent.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.