0
$\begingroup$

Wikipedia states that under certain circumstances, $\mathrm{BIC} $ can be calculated as: $$\mathrm{BIC} = n \ln(\mathrm{RSS}/n) + k \ln(n),$$

where $\mathrm{RSS}$ is the residual sum of squares. However, I was not able to find a reliable source for it. This question gives another source, however that source is just a copy of the Wikipedia article.

Yaffee and McGee state that

$$\mathrm{BIC} = n \ln(\mathrm{MSE}) + k \ln(n),$$

which IMHO would be identical to the Wikipedia definition, if they did not specify

$$\mathrm{MSE} = \frac{1}{n-k}(RSS).$$

That's a definition of $\mathrm{MSE}$ that I have never seen before (due to $-k$) and does not make a lot of sense to me.

Any references to reliable sources for BIC with residual sum of squares or an explanation of the strange definition of $\mathrm{MSE}$ is greatly appreciated.

Thank you.

$\endgroup$
2
  • $\begingroup$ The $-k$ is the standard adjustment for creating an unbiased estimator of residual variance in a regression, and serves the same purpose (well is exactly the same thing) as the $-1$ in the usual calculation of variance, where you divide by $n-1$. I'm a bit surprised you haven't run into it before :) $\endgroup$
    – jbowman
    Commented Mar 4, 2020 at 19:08
  • $\begingroup$ @jbowman Of course! Ok, I withdraw my hasty statement that I have never seen it before. Of course I have, I just did not make the connection because I'm used to only $1$ being subtracted. $\endgroup$
    – Nos
    Commented Mar 4, 2020 at 19:29

1 Answer 1

0
$\begingroup$

The formulas given by Yaffee and McGee and Wikipedia are indeed identical, except for Bessel's correction ($-k$). Whether Bessel's correction has to be applied depends on the use case.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.