I have a vector $\mathbf{x}$ of $n$ real random variables. The random variables can be assumed to follow a multivariate normal or log-normal distribution (assuming $\mathbf{x}>0$ is ok). I would like to analytically obtain the probability that the sum of the random variables decreases below a certain threshold, i.e. ${\mathbf{1}^T\mathbf{x}}\leq\sqrt{\mathbf{x}^T\mathbf{Q}\mathbf{x}}$, where $\mathbf{1}$ is a vector $n$ ones and $\mathbf{Q}$ is a positive definite $n$ x $n$ real matrix.
I cannot find the distribution of ${\mathbf{1}^T\mathbf{x}}-\sqrt{\mathbf{x}^T\mathbf{Q}\mathbf{x}}$ or ${\mathbf{1}^T\mathbf{x}}/\sqrt{\mathbf{x}^T\mathbf{Q}\mathbf{x}}$. Therefore I have started to look for alternative ways to find the probability: Is there any sense to find the maximum likelihood observation s.t. the constraint and then obtain the probability from a cdf? For example, could I apply the normal log-likelihood as follows:
$\arg\max$ $f(\mathbf{x} | \mathbf{\mu},\mathbf{\Sigma}) =\frac{1}{2} [\text{ln}(|\mathbf{\Sigma}|) + \text{n ln}\left (2\pi \right ) + (\mathbf{x}-\mathbf{\mu})^T\mathbf{\Sigma}^{-1}(\mathbf{x}-\mathbf{\mu})]$
subject to ${\mathbf{1}^T\mathbf{x}}-\sqrt{\mathbf{x}^T\mathbf{Q}\mathbf{x}} \leq 0$.
If this is nonsense please elaborate why.