I doubt you can; you certainly cannot precisely since you have $0.4375 = \frac{7}{16}$ and none of the folds have a length which is a multiple of $16$.
And I am not sure why you would want to: each fold is going to train on most of the data (about $90\%$ in your example) so will reflect something close to the overall proportion. For example
library(caret)
trainX <- mtcars %>% select(-c("vs", "am", "gear", "carb"))
trainY <- as.factor(mtcars$vs)
levels(trainY) <- list(yes=1, no=0)
set.seed(2021)
tcontrol_1 <- trainControl(method="cv", number=10, classProbs=TRUE,
summaryFunction=twoClassSummary)
model_fit <- train(x=trainX, y=trainY, method = "glmnet",
family = "binomial", standardize=TRUE,
trControl = tcontrol_1, metric = "Sens")
prop <- function(x, Y=trainY){ proportions(table(Y[x])) }
prop(1:length(trainY))
# yes no
# 0.4375 0.5625
sapply(model_fit$control$index, prop)
# Fold01 Fold02 Fold03 Fold04 Fold05 Fold06 Fold07
# yes 0.4285714 0.4482759 0.4137931 0.4482759 0.4285714 0.4137931 0.4482759
# no 0.5714286 0.5517241 0.5862069 0.5517241 0.5714286 0.5862069 0.5517241
# Fold08 Fold09 Fold10
# yes 0.4482759 0.4482759 0.4482759
# no 0.5517241 0.5517241 0.5517241
so they are close but not exact for the training folds. For the validation folds, they are even less close (with about three observations per fold, what would you expect?) but there does seem to be a fix to avoid total imbalance.
sapply(model_fit$control$indexOut, prop)
# Resample01 Resample02 Resample03 Resample04 Resample05 Resample06
# yes 0.5 0.3333333 0.6666667 0.3333333 0.5 0.6666667
# no 0.5 0.6666667 0.3333333 0.6666667 0.5 0.3333333
# Resample07 Resample08 Resample09 Resample10
# yes 0.3333333 0.3333333 0.3333333 0.3333333
# no 0.6666667 0.6666667 0.6666667 0.6666667