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I have the following problem:

enter image description here

Here is my approach:
With the activation function: $F(x) = x^2 + 2x + 3$, we can calculate the activation of the two units of the second layer by: $a_1^2 = F(w_{13}\cdot x_1 + w_{23}\cdot x_2) = F(2\cdot 1 + (-3)\cdot (-1)) = F(5) = 38$
$a_2^2 = F(w_{14}\cdot x_1 + w_{24}\cdot x_2) = F(1\cdot 1 + 4\cdot (-1)) = F(-3) = 6$

With new inputs, we can now calculate the Output by:
$h(x) = F(w_{35}\cdot a_1^2 + w_{45}\cdot a_2^2)$ = $F(2\cdot 38 + (-1)\cdot 6) = F(70) = 5043$

I was wondering whether my approach to the problem was correct or not?

I would really appreciate any comments. Thank you all!

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  • $\begingroup$ Please add the self-study tag & read its wiki. $\endgroup$
    – Sycorax ♦
    Mar 13 at 13:07
  • $\begingroup$ yes what you wrote is correct $\endgroup$
    – Alberto Sinigaglia
    Mar 13 at 23:47

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