All Questions
7 questions
1
vote
1
answer
100
views
Two sample proportions: How to test the hypothesis that the difference in proportions is less than a specified threshold?
Say I have treatment and control, perfectly randomized.
I have 70000 conversions for treatment in 80000 users.
I have 70100 converions for control in 800100 users.
My null hypothesis is that there is ...
2
votes
1
answer
130
views
What test to perform if I have percentage data
I have the following percentage data from multiple samples, and a corresponding reference percentage. Which test should I perform to test whether the percentage from the samples is different from the ...
0
votes
1
answer
128
views
Chi square goodness of fit test or individual test for proportion or both
I have dataset which looks like below -
Categories
Sample 1
Sample 2 ....
Sample 9
Reference Proportion
A
89
91
85
0.89
B
0
1
3
0.01
C
2
1
1
0.02
...
6
8
7
0.06
I
1
2
1
0.005
I want to test ...
1
vote
1
answer
70
views
Is this problem related to statistical inference from two population parameters? If so, why does my approach not give the right answer?
What I tried was use the statistic
z = pbar1 - pbar2 +- z of a/2 * SQRT[{pbar1*(1-pbar1)}/n1 + {pbar2*(1-pbar1)}/n2 ]
pbar1= 37/88 = .235
n1 = 88
n2=102
pbar2=.235
z = .42045-.235 +- 1.96 * SQRT[{....
3
votes
1
answer
7k
views
T test not for proportion
Why do we use Z test for proportions and why not T test. I have found a similar question here
but I am unable to get what the answer tries to convey. It would be of great help if anyone could explain ...
4
votes
1
answer
3k
views
Proportion Test: Z-test vs bootstrap / simulation - different results
I'm learning hypothesis testing, and going through the following example:
The CEO of a large electric utility claims that 80 percent of his 1,000,000 customers are very satisfied with the service ...
1
vote
0
answers
35
views
Experimental Design and Inference For Proportions
I have a specific example for an experimental design using a control/test group that I want to make inferences on. I want to test the completion rate for the same training program done online vs. ...