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Results for likelihood constant
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238 votes
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What is the difference between fixed effect, random effect in mixed effect models?

Here we outline five definitions that we have seen: Fixed effects are constant across individuals, and random effects vary. … (LaMotte, 1983) Fixed effects are estimated using least squares (or, more generally, maximum likelihood) and random effects are estimated with shrinkage (“linear unbiased prediction” in the terminology …
John Salvatier's user avatar
207 votes
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What are the advantages of ReLU over sigmoid function in deep neural networks?

One major benefit is the reduced likelihood of the gradient to vanish. This arises when $a > 0$. In this regime the gradient has a constant value. … The constant gradient of ReLUs results in faster learning. The other benefit of ReLUs is sparsity. Sparsity arises when $a \le 0$. …
DaemonMaker's user avatar
  • 2,987
131 votes
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Bayes regression: how is it done in comparison to standard regression?

On another hand, you could estimate such model using maximum likelihood estimation, where you would be looking for optimal values of parameters by maximizing the likelihood function $$ \DeclareMathOperator … This makes Bayes theorem proportional to the likelihood function alone, so the posterior distribution will reach its maximum at exactly the same point as the maximum likelihood estimate. …
Tim's user avatar
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125 votes
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Why do we use Kullback-Leibler divergence rather than cross entropy in the t-SNE objective f...

Side note: The cross entropy in this case turns out to be proportional to the negative log likelihood, so minimizing it is equivalent maximizing the likelihood. … section 2: "A natural measure of the faithfulness with which $q_{j \mid i}$ models $p_{j \mid i}$ is the Kullback-Leibler divergence (which is in this case equal to the cross-entropy up to an additive constant
user20160's user avatar
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122 votes
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What misused statistical terms are worth correcting?

Fisher who first used the term with this meaning, a parameter is an unknown constant to be estimated, say a population mean or correlation. … Fisher did hijack many pre-existing English words, including variance, sufficiency, efficiency and likelihood. More recently, J.W. …
105 votes
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Why to optimize max log probability instead of probability

To get a reasonable step size toward the optimum, we'd have to scale the gradient by the reciprocal of that, an enormous constant $\sim 10^{11}$. … This is because the likelihood is a big product with a bunch of terms, and the log turns that product into a sum, as noted in several other answers. …
Paul's user avatar
  • 11.1k
101 votes
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What is the reason that a likelihood function is not a pdf?

But, as pointed out by the reference to Lehmann made by @whuber in a comment below, the likelihood function is a function of the parameter only, with the data held as a fixed constant. … Perhaps even more important than this technical example showing why the likelihood isn't a probability density is to point out that the likelihood is not the probability of the parameter value being correct …
Macro's user avatar
  • 45.8k
92 votes
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What is the difference in Bayesian estimate and maximum likelihood estimate?

follow: Maximum Likelihood Estimate With MLE,we seek a point value for $\theta$ which maximizes the likelihood, $p(D|\theta)$, shown in the equation(s) above. … In other words, in the equation above, MLE treats the term $\frac{p(\theta)}{p(D)}$ as a constant and does NOT allow us to inject our prior beliefs, $p(\theta)$, about the likely values for $\theta$ in …
Zhubarb's user avatar
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90 votes
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Why is the L2 regularization equivalent to Gaussian prior?

This gives rise to a Gaussian likelihood: $$\prod_{n=1}^N \mathcal{N}(y_n|\beta x_n,\sigma^2).$$ Let us regularise parameter $\beta$ by imposing the Gaussian prior $\mathcal{N}(\beta|0,\lambda^{-1}),$ … Instead of a Gaussian prior, multiply your likelihood with a Laplace prior and then take the logarithm. …
ngiann's user avatar
  • 1,279
74 votes
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Why do we do matching for causal inference vs regressing on confounders?

First, that the treatment effect is constant across levels of the confounders, and second, that the linear model describes the conditional relationship between the outcome and the confounders. … Targeted Maximum Likelihood Estimation: A Gentle Introduction. 2009;17. Zivich PN, Breskin A. Machine Learning for Causal Inference: On the Use of Cross-fit Estimators. …
Noah's user avatar
  • 36.8k
73 votes
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Taleb and the Black Swan

shape" altogether and simply specify a relationship between the mean of a distribution and its variance (eg allowing the variance to increase proportionately to the square of the mean), using the "quasi-likelihood … The great weight you place on the fact that the variance of the Gaussian distribution is constant regardless of its mean (which causes problems with scalability), for instance, is invalid. …
Peter Ellis's user avatar
  • 17.8k
73 votes

Negative values for AIC in General Mixed Model

The AIC is defined as $$\text{AIC} = 2k - 2\ln(L)$$ where $k$ denotes the number of parameters and $L$ denotes the maximized value of the likelihood function. … as well as on page 63: Usually, AIC is positive; however, it can be shifted by any additive constant, and some shifts can result in negative values of AIC. [...] …
Sven Hohenstein's user avatar
67 votes
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Maximum Likelihood Estimators - Multivariate Gaussian

To obtain their estimate we can use the method of maximum likelihood and maximize the log likelihood function. … We can now re-write the log-likelihood function and compute the derivative w.r.t. …
Xavier Bourret Sicotte's user avatar
61 votes
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Are your chances of dying in a plane crash reduced if you fly direct?

Actual odds of planes crashing aside, you're falling into a logical trap here: ...each time one flies on an airplane, it does not increase the likelihood that he will die in a future airplane crash … It's approximately correct to assume constant chances of dying per flight because (as many have pointed out) most accidents happen on takeoff and landing. …
Shep's user avatar
  • 840
58 votes
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What are variational autoencoders and to what learning tasks are they used?

The difference is that the decoder doesn't assume that the mean of $p(\mathbf{x}|\mathbf{z})$ is linear in $\mathbf{z}$, nor it assumes that the standard deviation is a constant vector. … Intuitively we want latent variables $\mathbf{z}$ which maximize the likelihood of generating the $\mathbf{x}_i$ in the training set $D_n$. …
DeltaIV's user avatar
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