Search Results
Search type | Search syntax |
---|---|
Tags | [tag] |
Exact | "words here" |
Author |
user:1234 user:me (yours) |
Score |
score:3 (3+) score:0 (none) |
Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
Views | views:250 |
Code | code:"if (foo != bar)" |
Sections |
title:apples body:"apples oranges" |
URL | url:"*.example.com" |
Saves | in:saves |
Status |
closed:yes duplicate:no migrated:no wiki:no |
Types |
is:question is:answer |
Exclude |
-[tag] -apples |
For more details on advanced search visit our help page |
EDA stands for "Exploratory data analysis". Developed by Tukey to contrast with Confirmatory Data Analysis or CDA (the formal testing of hypotheses). EDA is typically concerned with describing data numerically and graphically to make the data easier to understand and to yield new insights.
3
votes
Is there any good reason to use PCA instead of EFA? Also, can PCA be a substitute for factor...
(This is really a comment to @ttnphns's second answer)
As far as the different type of reproduction of covariance assuming error by PC and by FA is concerned, I've simply printed out the loadings/com …
1
vote
Difference between exploratory and confirmatory factor analysis in determining construct ind...
If I understand your question correctly it is a question about testing. Then simply testing requires a kind of confirmatory factor-analysis, the same as the question: "do the means in the subgroups re …
1
vote
Is there any good reason to use PCA instead of EFA? Also, can PCA be a substitute for factor...
In my view, the notions of "PCA" and "FA" are on a different dimension from that of notions of "exploratory", "confirmatory" or maybe "inferential". So each of the two mathematical/statistical meth …
1
vote
Is there any good reason to use PCA instead of EFA? Also, can PCA be a substitute for factor...
Just one additional remark for @amoebas's long (and really great) answer on the character of the $\Psi$-estimate.
In your initial statements you have three $\Psi$: for PCA is $ \Psi = 0$, …