So I'm supposed to perform a hypothesis test with:
sample size = 27$27$
sample mean = 10.7$10.7$
sample standard deviation = 3.6$3.6$
Hypothesized mean, $\mu_0=11$
Because the sample size is small and population standard deviation is unknown, I have to perform a t-test to see if I can reject my null hypothesis.
I find that the t-score is -0.43$-0.43$ and:
$p-value =2p(t_{26} > 0.43)$$\text{p-value} =2p(t_{26} > 0.43)$
This is the t-table I will be provided in tests/exams at my school: https://drive.google.com/file/d/0BxUaD_pbAL2hQzE0dzZtVHhsSlU/view
There is no value close to 0.43$0.43$ in the row of df = 26$\text{df} = 26$ on the t-table, so what do I do?
Am I supposed to use the z-table instead? Or is using R or some other computational program the only possible way to find the p-value?
Also, regarding the t-table I linked, is this table only for one-tailed t-tests? If so, what do I do if I need to do a two-tailed test (like in this example)?