0
$\begingroup$

Hi I have a large data set of objects, each containing a set of the same attributes. The attributes are measured quantities like height, width, etc. The data is arranged in a time series so that the value for an attribute for an object is indexed by its time. I want to create a multivariate model of the attributes but was not sure if I should look into parametric or non-parametric methods. Most of the attributes are correlated and dependent on one another so when creating a model I need to have variables representing the other attributes in some way. One of my ultimate goals is to perform time series data mining for intervention analysis. Should I be using hierarchical models since I have multiple objects? Can this possibly be a survival model using a time-to-failure distribution? Any suggestions for methods to look at would be helpful. An example of what my data looks like is shown below. Thanks enter image description here

$\endgroup$
4
  • $\begingroup$ There is no information here on what the "attributes" are. $\endgroup$
    – Nick Cox
    Commented Jul 8, 2015 at 17:46
  • $\begingroup$ Statistically, they can each come from different families of distributions. $\endgroup$
    – cavs
    Commented Jul 8, 2015 at 19:28
  • 1
    $\begingroup$ Still no information! Do you mean something qualitative, counted, measured? $\endgroup$
    – Nick Cox
    Commented Jul 8, 2015 at 19:45
  • $\begingroup$ Sorry, they are all measure quantities like height, width, etc. $\endgroup$
    – cavs
    Commented Jul 8, 2015 at 20:01

1 Answer 1

2
$\begingroup$

If your objective is Intervention Detection then you definitely want to use parametric methods. When you construct an ARIMA model it is possible to detect pulses , level shifts , seasonal pulses and local time trends using procedures suggested by Tsay and others as described here.

Take a look at the flow diagram in http://www.autobox.com/cms/index.php/blog/entry/build-or-make-your-own-arima-forecasting-model to give you some guidance.

$\endgroup$
0

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.