Is there any difference between stride and subsample in convolutional neural networks?
2 Answers
Remark
Any strided convolutional or subsampling layer does achieve downsampling of the input. So, in a way, refering to "subsampling" in the context of a convolutional layer probably signifies using stride. strides
for Convolutional2D
layers was called subsample
in Keras 1.2.2, for example (now it has been changed to simply strides
in Conv2D
).
On Subsampling, Mean Pooling, and Convolutional layers
If you mean "subsample" as in the use of Subsampling layers, Subsampling is a generalization of Mean Pooling, with learnable weights. It may, or may not use striding.
See the output in Torch for SpatialSubsamplng:
$$\text{output}[i][j][k] = \text{bias}[k] + \text{weight}[k] \sum_{s=1}^{kW} \sum_{t=1}^{kH} \text{input[}dW\cdot(i-1)+s)][dH\cdot(j-1)+t][k]$$
The output has the same number of channels $k$ as the input.
And here's the output of SpatialAveragePooling
$$\text{output}[i][j][k] = {1\over kW\cdot kH} \sum_{s=1}^{kW} \sum_{t=1}^{kH} \text{input[}dW\cdot(i-1)+s)][dH\cdot(j-1)+t][k]$$
The only difference between both is that Subsampling allows different weights per channel. But a channel from the input maps to the same channel in the output.
Compare it to the output of SpatialConvolution, where all channels in the input contribute to all channels in the output:
$$\text{output}[i][j][k] = \text{bias}[k] + \sum_l \sum_{s=1}^{kW} \sum_{t=1}^{kH} \text{weight}[s][t][l][k] \cdot \text{input}[dW\cdot(i-1)+s)][dH\cdot(j-1)+t][l]$$
So, that's it, Subsampling is not generally equivalent to strided Convolution, because their mappings are different.
Stride is a hyper parameter used in subsampling that changes how the convolution operation is done over the input that is being subsampled. If you google search these two terms there is endless information that describes them.
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1$\begingroup$ This answer is currently the top result for a google search for
stride subsample
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