3
$\begingroup$

I have $n$ individuals, and for each individual, I have two measurements using two devices (device X and device Y). I know the ground truth for the correct measurement, and I can classify each measurement as accurate or inaccurate. Thus, for each individual I effectively have a boolean value that indicates whether device X was correct or not (say $x_i$) and a boolean value that indicates whether device Y was correct or not (say $y_i$).

Is there a good statistical test to use to compare the accuracy rate of the two devices?

In particular, suppose I notice that device X's accuracy rate appears to be higher than device Y's accuracy rate, based upon the $n$ observations (i.e., $(x_1+\dots+x_n)/n > (y_1+\dots+y_n)/n$, where $x_i,y_i = 1$ means it was correct and $0$ means it was incorrect). Now I'd like to test whether the difference in observed accuracy rate is statistically significant. Can I compute a $p$-value for the null hypothesis that their underlying accuracy rate is actually the same?

Should I use the Wilcoxon signed-rank test? A paired Student's t-test? Some sort of paired Welch t-test (does such a thing even exist)? None of those seems like an obvious fit to me: I know the data isn't normally distributed (it presumably has a Bernoulli distribution), so a t-test isn't perfect (on the other hand I've read that in practice the t-test is fairly robust to deviations from normality so maybe it is OK?); and I can't tell whether a Wilcoxon signed-rank test takes into account the prior knowledge that the data is Bernoulli distributed. Anyway, what would be the most appropriate methodology?

$\endgroup$
2
  • $\begingroup$ Sounds like you probably want McNemar's test $\endgroup$
    – Glen_b
    Commented May 31, 2014 at 3:46
  • $\begingroup$ see also here $\endgroup$
    – Glen_b
    Commented May 31, 2014 at 3:49

1 Answer 1

4
$\begingroup$

McNemar's test solves this problem. (Thanks to Glen_b for mentioning this!) It is intended for paired data, where the observations are boolean -- a perfect fit. It is also easy to compute, which is convenient.

See also Paired t-test for binary data for another instance of a closely related statistical hypothesis testing problem.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.