# Odds Ratio from Sample size, mean and SD

I do have the following data

TABLE A
Population Size | Type    | Value
340             | Control | .7+03[SD]
350             | Test    | .015+.25[SD]


Can I convert this to something like this? How ?

TABLE B
Population Size | Type    | Value
340             | Control | 25
350             | Test    | 33


If not how to I convert TABLE A into a Odds Ratio (based on Mean and SD only)

It would be possible if the mean is the mean of a binary variable coded using the values 0 or 1. In that case, the mean would actually be the proportion of 1s. In that case the odds of a 1 would be $\frac{0.7}{1-0.7}\approx 2.3$, i.e. within the control group we expect to find 2.3 1s for ever 0. The odds of a 1 for the test group would be $\frac{0.015}{1-0.015}\approx 0.015$. The odds ratio would than be just the ratio of those odds: $\frac{\frac{.7}{1-.7}}{\frac{0.015}{1-0.015}} = \frac{0.7}{1-0.7} \times \frac{1-0.015}{0.015}= \frac{0.7(1-0.015)}{(1-0.7)0.015}\approx153$, that is the odds of a 1 in the control group is a 153 times larger than the odds of a 1 in the test group.
However, your means are not proportions, so this method won't work for you. I know this because if the mean for the control group were a proportion, then the standard deviation would have been $\sqrt{0.7*(1-0.7)}\approx0.46$, which is completely different from the standard deviation you report in the table.