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I have a binary logistic regression with just one binary fixed factor predictor. The reason I don't do it as a Chi square or Fisher's exact test is that I also have a number of random factors (there are multiple data points per individual and individuals are in groups, although I don't care about coefficients or significances for those random variables). I do this with R glmer.

I would like to be able to express the coefficient and associated confidence interval for the predictor as a risk ratio rather than an odds ratio. This is because (maybe not for you but for my audience) risk ratio is much easier to understand. Risk ratio here is the relative increase in chance of the outcome being 1 rather than 0 if the predictor is 1 rather than 0.

The odds ratio is trivial to get from the coefficient and associated CI using exp(). To convert an odds ratio to a risk ratio, you can use "RR = OR / (1 – p + (p x OR)), where p is the risk in the control group" (source: http://www.r-bloggers.com/how-to-convert-odds-ratios-to-relative-risks/). But, you need the risk in the control group, which in my case means the chance that the outcome is 1 if the predictor is 0. I believe the intercept coefficient from the model is in fact the odds for this chance, so I can use prob=odds/(odds+1) to get that. I'm pretty much so-far-so-good on this as far as the central estimate for the risk ratio goes. But what worries me is the associated confidence interval, because the intercept coefficient also has its own associated CI. Should I use the central estimate of the intercept, or to be conservative should I use whatever limits of the intercept CI make my relative risk CI widest? Or am I barking up the wrong tree entirely?

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  • $\begingroup$ Possible duplicate of Logistic Regression in R (Odds Ratio) $\endgroup$
    – Minnow
    Commented Nov 27, 2015 at 18:17
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    $\begingroup$ This is in no way a duplicate of that question. I have no problems getting odds ratios, it is risk ratios that I wonder about. They aren't mentioned in that question. $\endgroup$
    – Amorphia
    Commented Nov 29, 2015 at 15:13
  • $\begingroup$ See Poisson regression with robust standard errors: stats.stackexchange.com/questions/18595/… $\endgroup$
    – user16263
    Commented Oct 4 at 15:18

2 Answers 2

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Zhang 1998 originally presented a method for calculating CIs for risk ratios suggesting you could use the lower and upper bounds of the CI for the odds ratio.

This method does not work, it is biased and generally produces anticonservative (too tight) estimates of the risk ratio 95% CI. This is because of the correlation between the intercept term and the slope term as you correctly allude to. If the odds ratio tends towards its lower value in the CI, the intercept term increases to account for a higher overall prevalence in those with a 0 exposure level and conversely for a higher value in the CI. Each of these respectively lead to lower and higher bounds for the CI.

To answer your question outright, you need a knowledge of the baseline prevalence of the outcome to obtain correct confidence intervals. Data from case-control studies would rely on other data to inform this.

Alternately, you can use the delta method if you have the full covariance structure for the parameter estimates. An equivalent parametrization for the OR to RR transformation (having binary exposure and a single predictor) is:

$$RR = \frac{1 + \exp(-\beta_0)}{1+\exp(-\beta_0-\beta_1)}$$

And using multivariate delta method, and the central limit theorem which states that $\sqrt{n} \left( [\hat{\beta}_0, \hat{\beta}_1] - [\beta_0, \beta_1]\right) \rightarrow_D \mathcal{N} \left(0, \mathcal{I}^{-1}(\beta)\right)$, you can obtain the variance of the approximate normal distribution of the $RR$.

Note, notationally this only works for binary exposure and univariate logistic regression. There are some simple R tricks that make use of the delta method and marginal standardization for continuous covariates and other adjustment variables. But for brevity I'll not discuss that here.

However, there are several ways to compute relative risks and its standard error directly from models in R. Two examples of this below:

x <- sample(0:1, 100, replace=T)
y <- rbinom(100, 1, x*.2+.2)
glm(y ~ x, family=binomial(link=log))
library(survival)
coxph(Surv(time=rep(1,100), event=y) ~ x)

http://research.labiomed.org/Biostat/Education/Case%20Studies%202005/Session4/ZhangYu.pdf

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  • $\begingroup$ AdamO, your answer is the closest I have come to what I am looking for. Can you please point me in the direction of deriving the RR from the OR of a multivariable multistate model? $\endgroup$
    – altfi_SU
    Commented May 28, 2020 at 14:33
  • $\begingroup$ @altfi_SU I implemented this in the epitools package as probratio. Note contact is woefully out of date :( rdrr.io/cran/epitools/man/probratio.html $\endgroup$
    – AdamO
    Commented May 28, 2020 at 17:03
  • $\begingroup$ Thanks, @AdamO. Good to know this package exists. However, I am working with published results of a multivariable model and therefore can't pass a glm object as an argument to the probratio function. I need to find the RR in a meta-analysis. Any lead in the form of mathematical notation as you wrote above? $\endgroup$
    – altfi_SU
    Commented May 29, 2020 at 7:41
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Table 2 in the paper by "Sensitivity Analysis in Observational Research: Introducing the E-Value" by Tyler J. VanderWeele and Peng Ding summarises how to approximate risk ratio from odds ratio.

Also, from what I understand, odds in logistic regression based on case-control data cannot be used to calculate probability, therefore, cannot be directly used to calculate risk.

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