3
$\begingroup$

I'm trying to find an asymptotic approximation for the expectation of the maximum of $n$ Weibull random variables $X_i \sim Weibull(\lambda,\beta)$ when $\beta < 1/2$ and $n$ is large. From simulations, I'm getting that

$$E[max(X_1,...,X_n) ] \approx A n^{c}$$ for some constant $A$ and constant $c < 1$, but I'm not sure how to prove something like this.

Are there any well-known approximations for the expectation of the maximum of Weibull random variables?

$\endgroup$

1 Answer 1

3
$\begingroup$

An exact formula is given by "A note on order statistics from Weibull distribution" by Balakrishnan and Joshi. Define $$J(p,0) = \frac{\Gamma\left(\frac{1}{\beta}\right)}{\lambda\beta p^{1/\beta}}$$ with $$J(p,m) = J(p,m-1) - J(p+1,m-1) $$ Define $\alpha_n$ as the expected value of the $n$th smallest sample. Then the expected value of the smallest sample is $$\alpha_1 = J(1,0)$$ and for larger samples is $$ \alpha_r = \alpha_{r-1} + \binom{N-1}{r-1}J(N-r+1,r-1)$$

$\endgroup$
1
  • 2
    $\begingroup$ Thanks! I also found the following slightly more explicit formula for the expectation of the maximum on a book by Chin-Diew Lai called "Generalized Weibull Distributions" $$ E[max(X_1,...,X_n)] = n \Gamma(1+1/\beta) \sum_{i=0}^{n-1} \binom{n-1}{i} (-1)^i (\frac{1}{i+1})^{1 + 1/\beta}$$ $\endgroup$
    – Asterix
    Commented Jun 20, 2017 at 17:22

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.