I apologize if my question is extremely simple, but you know my name.
I have only the variance of a sample and its 95% confidence intervals, nothing more, nothing less.
Please correct me if I am wrong: I know that
sd = sqrt(variance), can I compute the standard deviation and its 95% confidence intervals squaring the estimate and confidence intervals of the variance of the sample?
I read How can the confidence interval for standard deviation not include the sample standard deviation?, but I do not know if the sample originated from a normal distribution and I do not know
(I use R)
Edit, at the request of whuber:
I apologize and I hope that it will be clearer than my previous question. I am talking about calculating the standard deviation and its 95% confidence intervals from the variance and its 95% confidence intervals, without any other info. I do not know how they were calculated, I do not know if the distribution was normal. If sd=sqrt(var), my question is similar to asking how you can backtransform a variable and its 95% confidence intervals (unfortunately I did not find relevant Q&A here).