# Required number of simulations for Monte Carlo analysis

My question is about the required number of simulations for Monte Carlo analysis method. As far as I see the required number of simulations for any allowed percentage error $E$ (e.g., 5) is $$n = \left\{\frac{100 \cdot z_c \cdot \text{std}(x)}{E \cdot \text{mean}(x)} \right\}^2 ,$$

where $\text{std}(x)$ is the standard deviation of the resulting sampling, and $z_c$ is the confidence level coefficient (e.g., for 95% it is 1.96). So in this way it is possible to check that the resulting mean and standard deviation of $n$ simulations represent actual mean and standard deviation with 95% confidence level.

In my case I run the simualtion 7500 times, and compute moving means and standard deviations for each set of 100 sampling out of the 7500 simulations. The required number of simulation I obtain is always less than 100, but % error of mean and std compare to mean and std of entire results is not always less than 5%. In most cases the % error of mean is less than 5% but the error of std goes up to 30%.

What is the best way to determine number of required simulation without know actual mean and std (in my case subjected outcome of simulation is normally distributed)?

Thanks in advance for any help.

In order to have an idea about what may distribution of simulation results look like when iteration is run infinite number of times: Instead of using resulted mean and variance after n number of simulations, I've decided to find a fit function of resulted distribution, but here n has to fullfill allowed % error. I think on that way I can find more correct results on cumulative distrubution function that is related with e.g. 97.5%. Because when I compare the results of 400 and 7000 simulation, fit functions of distribution for both sampling looks like each other only curve of 2nd one is smoother. Also, hence model in MATLAB/Simulink is nonlinear, although generated input parameters are normal distributed, resulted histogram of simulations are not normal for that reason I used "generalized extreme value distribution", which is named as 'gev' in MATLAB. But still, I am quite not sure about this methodolgy, thanks for any command in advance

• as far as I see when the outcomes of simulation is evaluated by any pass criteria, it is possible to find out required number of simulation for any confidence level, but in my case I want to find out mean and variance of entire result with specific confidence level with any finite number of iterations. Hence for any n samples, variance is used to define interval of mean, but indeed I need variance as well to find any value that may represents CPDF of 0.975. thanks for any comment – maxwell May 3 '14 at 12:08

The typical way to determine the required number of simulations is by computing the variance of the simulation $\hat\sigma_N^2$ for N paths, then the standard error is $\frac{\hat\sigma_N}{\sqrt{N}}$, see section on error estimation of MC in "Monte Carlo Methods in Finance" by Peter Jackel, also a chapter "Evaluating a definite integral" in Sobol's little book