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What are hierarchical priors?

How do they differ from the general concept of priors?

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2 Answers 2

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A regular Bayesian model has the form $p(\theta |y) \propto p(\theta)p(y|\theta)$. Essentially the posterior is proportional to the product of the likelihood and the prior. Hierarchical models put priors on the prior (called a hyperprior) $p(\theta |y) \propto p(y|\theta)p(\theta |\lambda)p(\lambda)$. We can do this as often as we want.

See Gelman's "Bayesian Data Analysis" for a good explanation.

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When you have a hierarchical Bayesian model (also called multilevel model), you get priors for the priors and they are called hierarchical priors.

Consider for example:

$z = \beta_0+\beta_1{y}+\epsilon, \\ \epsilon \mathtt{\sim} N(0,σ)\\ \beta_0\mathtt{\sim} N(\alpha_0,σ_0), \beta_1\mathtt{\sim} N(\alpha_1,σ_1), \beta_2\mathtt{\sim} N(\alpha_2,σ_2)\\ \alpha_0\mathtt{\sim} inverse-\gamma(\alpha_{01},\theta_0)\\ $

In this case, you can say that, $inverse$-$\gamma$ is a hyperprior.

EDIT: This was very useful to me when I learned about Hierarchical Bayesian Modeling. For an in depth explanation and detail, you may refer to Gelman's Data Analysis Using Regression and Multilevel/Hierarchical Models.

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  • $\begingroup$ you get priors for the parameters of the priors $\endgroup$ Commented Apr 9, 2012 at 15:26
  • $\begingroup$ Why do you need to parametrize the parameters? $\endgroup$
    – skan
    Commented Apr 25, 2023 at 7:42

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