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4
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1
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Joint Distribution of Discrete and Continuous
Suppose i have two random variables, $X$ and $Y$. WLOG assume $X$ is discrete, and $Y$ is continuous.
How do we define the joint distribution between $X$ and $Y$? … EDIT: i should note that, I'm wondering how can it be defined and calculated in terms of PDF and CDF. …
3
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1
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645
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Joint distribution of a discrete and a continous random variable
Get the joint distribution first:
$$P(X=x|P=p) = \frac{f_{X,P}(x,p)}{f_P(p)} \implies f_{X,P}(x,p) = P(X=x|P=p)f_P(p)$$
$$ f_{X,P}(x,p) = p^x(1-p)^{1-x} \qquad (0\le p \le 1 \text{ and } x=0,1)$$
I am … not sure if this is the correct joint distribution? …
6
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3
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463
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Joint pdf of a continuous and a discrete rv
Let $Y_j$ be distributed $\exp(Q_j)$ where $j=1, 2$.
If component 1 fails first, then $Y_1$ is observed but $Y_2$ is not ($Y_2$ is censored). … How can I derive the joint pdf of a continuous variable $u = \min(Y_1, Y_2)$ and a discrete variable $V = 1$ if $Y_1 < Y_2$ and $0$ otherwise? …
3
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2
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3k
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Express expectation value of a joint distribution over a discrete and continuous random vari...
Let $Y$ be a discrete random variable and let $X$ be an (absolutely) continuous random variable and $f(X, Y)$ a function of these two random variables. Let $P(X, Y)$ be the joint probability measure. … I am now wondering how to properly write the joint expectation value
$\mathbb{E}[f(X, Y)]$? …
1
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1
answer
193
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Joint and Posterior Distributions of Continuous and Discrete R.V.s
Yet since $X$ is discrete, I am not sure if I am allowed to move it inside the integral. I understand that there may be many flaws to my approach, so please enlighten me. … Calculate the conditional distribution of $P$ given $X=1$. …
1
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1
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5k
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Expected value (Mean) of a joint distribution
I saw in a textbook that if we have a joint distribution $f(X,Y)$ that is a Gaussian distribution, then we have the mode equal to the mean. … I suppose in a discrete case, it would just be $p_1[X_1, Y_1]' + p_2[X_2,Y_2]'$ (assuming there are only two possible values for $X,Y$) but I don't know how to transform this into continuous case. …
1
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1
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443
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Maximum likelihood joint probability distribution (discrete & continuous)
In each experiment, $v_1$ and $v_2$ are corrupted with zero mean Gaussian noise, and then compared to each other, and the maximum of the two is reported. … I observe two samples, $v^o_1$ and $v^{o}_2$, sampled from a Gaussian distribution with mean equal to $v_1$ and $v_2$ (respectively) and standard deviation $\sigma_v$ (equal for the two observations). …
1
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1
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149
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Is this a conditional distribution or joint, or none?
Variable #1 is called "p-value" and has 4 categorical levels. Variable #2 is called "Bayes Factor" and has 7 categorical level.
Question
Is what I have a contingency table? … In other words, does the table I'm showing below indicate the conditional frequency distribution of one variable given the other or the joint frequency distribution of the two variables together? …
1
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1
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149
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Joint "density" of data and indicators in Bayesian mixture model
But then the authors write:
The joint distribution of the observed data $y$ and the unobserved indicators $z$ conditional on the model parameters can be written
$$p(y, z\mid\theta,\lambda) = p(z\ … From the perspective of probability theory we can not just multiply
$p(y\mid z,\theta)$ and $p(z\mid\lambda)$, as the former is the pdf of a
continous random variable and the latter is the pmf of a discrete …
0
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1
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237
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questions related to joint distribution and continuous and discrete random variables [duplicate]
(a) If $U$ and $V$ are jointly continuous, show that $P(U =V) = 0$.
(b) Let $X$ be uniformly distributed on $(0,1)$, and let $Y= X$. Then, $X$ and $Y$ are continuous, and $P(X=Y) = 1$. … (b) $X$ is uniformly distributed on $(0, 1)$, so we have the distribution function $F(x) = x$ for $x \in (0,1)$. Then, we have an integrable function $f(x) = 1$ such that $\int_0^x 1 dx = x = F(x)$. …
0
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1
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215
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How do I find the constant of a continuous joint probability distribution function in R?
Consider the joint probability density function $f_{XY} (x, y) = c(x+y)$ over the range $0 < x < 3$ and $x < y < x + 2$.
I know how to do this for a joint discrete distribution, e.g. … y when they're continuous, so I'd really appreciate any help! …
1
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1
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119
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Expected value of joint discrete continuous distribution
This is a problem from All of Statistics by Wasserman that I have been struggling with for a while.
Problem
Let $X \sim \text{Uniform}(0,1)$. Let $0<a<b<1$. Let
\begin{equation}
Y =
\begin{cases}
1 & …
9
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2
answers
7k
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Does Bayes theorem apply to joint distributions of discrete and continuous random variables?
If random variables $X,Z$ are jointly distributed, with $f_X(x)$ continuous density of $X$ and $p_Z(z)$ the discrete probability mass at $Z=z$, does Bayes theorem hold in the sense that $$p_{Z|X}(z) = … $$ If not, is there an analogue for such discrete-continuous mixtures? …
1
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1
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176
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Is outer product of marginal distribution the "best" mean-field approximation for a joint di...
All the explanations I come across deal with gaussians and continuous distributions which are too much for me to handle right now. … I want to just understand the simplest case of discrete distributions first, and I'm unable to find the resource online, so here's where I need help.
The set up is as follows. …
3
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1
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CDF and MGF of a Sum of a discrete and continuous random variable
Compute the Moment Generating Function (MGF) $M_{z}(t)$ of $Z$
Compute the Distribution Function (CDF) $F_{z}$ of $Z$. Is $Z$ an absolutely continuous random variable? … From the theory I have studied, I have some questions regarding how to deal with this kind of exercises:
When it comes to sum to sum two independent random variables (discrete or continuous) and then …