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Results for gauss* mixture generate and not containing means
Search options not deleted score>= 1
1 vote
1 answer
65 views

Stochastic blockmodel with continuous weights in [0,1]

I do understand that the Gaussian model in the SBM does not necessarily imply that the weights have to be Gaussian distributed overall as it can be a mixture of different Gaussians for within and between … for strongly non-Gaussian weights? …
Christian Hennig's user avatar
3 votes
0 answers
75 views

Interpretation of generalized eigenvalues, matrix distance, information geometry

This question is about how generalized eigenvalues of two covariance matrices relate to the discriminability of their associated Gaussian distributions. … It is clear how the individual $\lambda_i$'s of a pair of covariance matrices reflects how discriminable their 0-mean Gaussians are along the corresponding $\Phi_i$. …
dherrera's user avatar
  • 1,415
1 vote

How to fit a Bayesian model to a mixture of Beta and One-Zero inflated data?

for the mixture, let's split into three components temporarily: The two discrete components The continuous component, which will be a mixture of two beta. … the advantage here is that the probability of each component can be fit wihtout considering the precise value of $Y$, only whether it is $0, 1$ or in-between. we can fit this with any gaussian process …
Guillaume Dehaene's user avatar
2 votes
2 answers
204 views

How to compare two PMF generating functions?

Assume the two distributions (of differences) are Gaussian, and do a simple Z-test. Is this valid and is there a better approach? … As @whuber implied, the histograms do not look Gaussian. With two big peaks around 0 and some constant which is the result when the probabilities differ at most one element. …
ilija139's user avatar
2 votes
Accepted

Variable selection strategies

Spike-and-slab: the model parameters are assumed to follow a Mixture of gaussians. However, the posterior is hard to sample from due to the nature of the prior. …
Mangnier Loïc's user avatar
2 votes
1 answer
90 views

How to tell the difference between a Latent Variable and a Non-Latent Variable?

The most popular example that comes up in this regard is the Gaussian Mixture Model: $$p(x, \pi_1, \pi_2, \mu_1, \sigma_1, \mu_2, \sigma_2 ) = \pi_1 \cdot N(x | \mu_1, \sigma_1) + \pi_2 \cdot N(x | \mu … Why cannot MLE be implemented for Gaussian mixture model directly? Why is the marginal likelihood difficult/intractable to estimate? …
stats_noob's user avatar
1 vote
1 answer
126 views

Generate marginally dependent (with predetermined covariance) but conditionally independent ...

I want to produce data with the following generative process which corresponds to a Mixture of Gaussians (MoG): $$ \begin{align} y\sim & Ber(p)\\ \mathbf{x}\sim & \mathcal{N}(\mu_y, \Sigma_y), \end{align …
Sergio's user avatar
  • 336
1 vote
Accepted

Jacobian and proposal ratio of Birth/death step in RJMCMC of Gaussian mixture model

probability of generating a certain realisation $w_{𝑗^∗}$ This is a product of the probability to propose a death/birth move when having $k+1$/$k$ components and of the density of the proposed new mixture … [Imho, a simpler representation of the moves would be to express the mixture in terms of unnormalised weights divided by their sum.] …
Xi'an's user avatar
  • 108k
1 vote

What is the benefit of latent variables?

Take a simple case: the data $x$ is a mixture of Gaussians generated by picking a cluster index $z$ (from a categoric distribution $p(z)$) and then sampling from the Gaussian of that cluster $p(x|z)$. … For example, in the mixture of Gaussians case, inferring $z$ identifies the cluster of each data point, which may be semantically meaningful. …
Carl's user avatar
  • 207
1 vote
0 answers
85 views

How to choose between a random-effects and a finite mixture model?

the mixture is over the distribution of $\gamma$. … Lastly, if we specify a distribution (say gaussian) for $\gamma$ in the mixture model thereby allowing for infinite values of $\gamma^{}_{i}$, are we back to a random effects world? …
lasoon's user avatar
  • 103
3 votes

p(x) in Gaussian mixture model

But, for instance, a sum of $K$ Gaussian random variables, $X_1+\cdots+X_K$, is still a Gaussian, whereas a random variable whose density is the sum of Gaussian densities (as the case in question) is not … Gaussian. …
utobi's user avatar
  • 12.1k
5 votes
1 answer
381 views

Is the likelihood for Gaussian mixture models still multimodal when Y is partially observed?

In discussing Gaussian mixture models (GMMs), https://normaldeviate.wordpress.com/2012/08/04/mixture-models-the-twilight-zone-of-statistics/ highlights the issue of Multimodality of the Likelihood. … variance-covariance matrix for each of the $k$ components separately, and in this case the likelihood has a single maximum and a relatively simple closed-form solution (see Maximum Likelihood Estimators - Multivariate Gaussian
Adrian's user avatar
  • 4,404
3 votes

what is the difference between mixture of two normal distributions and sum of two independen...

To get a sample from the mixture, you pick either $X$ or $Y$, with probabilities given by the mixing proportions. … The distribution of the mixture isn't; a mixture of two Normals is bimodal, because you get an observation from one or the other. …
Thomas Lumley's user avatar
3 votes

Bayesian priors associated with regularization penalties

The paper that you refer to by Hans (2011) "broadens the scope of the Bayesian connection by providing a complete characterization of a class of prior distributions that generate the elastic net estimate … $\ell_0$ regularization can be thought (Polson and Sun, 2017) as using a prior that is a mixture of Dirac delta centered at zero $\delta_0$ and a Gaussian $$ \pi(\beta_i) \propto (1 - \theta) \delta_0 …
Tim's user avatar
  • 141k
1 vote
0 answers
85 views

Maximum likelihood estimation when the model is misspecified (and the true data generating p...

I use $H$ instead of $F$ because the distributions may belong to different families: for example, if $F$ is Gaussian, $H$ (which is a mixture of Gaussians) will in general be non-Gaussian. … Here is a specific example (although I am interested in the general case described above): $H$ is a mixture of two Gaussians Component 1 has weight $\pi_1 = 0.5$ and is $\mathcal{N}(\mu, \sigma^2_1)$ …
Adrian's user avatar
  • 4,404

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